Answer:


Explanation:
The Newton's law in this case is:

Here,
is the air temperture, C and k are constants.
We have
in
So:

And we have
in
, So:

Now, we have:

Applying (1) for
:

Applying (1) for
:

Answer:
The value of the inductance is 1.364 mH.
Explanation:
Given;
amplitude current, I₀ = 200 mA = 0.2 A
amplitude voltage, V₀ = 2.4 V
frequency of the wave, f = 1400 Hz
The inductive reactance is calculated;

The inductive reactance is calculated as;

where;
L is the inductance

Therefore, the value of the inductance is 1.364 mH.
Answer:
F = 100 Newtons
Explanation:
F = ?
m = 0.04kg
u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.
s = 50m ==> s is just an abbreviation for distance, it is conventional.
v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

Then F = ma = 0.04 x 2500 = 100N
In order to have a period that matches the Earth's rotation, a satellite must be in a circular orbit, and 42,164 km from the center of the Earth.
But that's not quite enough to make sure that it always stays over the same point on the Earth's surface (and appears motionless in the sky). For that to happen, the satellite's orbit has to be directly over the Equator.
The Moon has nothing to do with any of this.
Based on the length of side of the cube given, the length of the needle is 2.28 inches.
<h3>What is the length of the needle?</h3>
The length of the side of a cube and its diagonal are related by the formula below:

where s is length of side



Therefore, the length of the needle is 2.28 inches
Learn more about length of diagonal of cube at: brainly.com/question/800212
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