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larisa86 [58]
3 years ago
13

Cornelsen Fokus Physik Lösungen

Physics
1 answer:
serious [3.7K]3 years ago
7 0

Cornelsen focus on physics solutions

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In 1939 or 1940, Emanuel Zacchini took his human-cannonball act to an extreme. After being shot from a cannon, he soared over th
Arlecino [84]
 We first determine the vertex by using the formula,<span>-b/2a = vertex, in order to get the values for the t-coordinate. That is why we got 
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v_y=26.5 sin(53)=21.163v_x=26.5 cos(53)=15.948 
then

let x=0since you are going to land on a 3m tally=-.5(9.8)t^2+ 21.163*t
y=0=-4.9t+21.163t=4.31
vx*4.31= total distance travelled=68.88m
Then for the first wheel, you have 15.948m=vxdetermine the time when he reaches 23 meters, that is

23/15.948=1.44218 sec

substitute t with1.44218 sec, then determine the height.
h(1.44218)=20.329

determine vertex by using a graphing calculatort=2.1594s h=22.85m
using the time value of the vertex, determine horizontal distance travelled
34.438m away from cannon
8 0
3 years ago
Where in the circuit of (Figure 1) is the current the largest, (a), (b), (c), or (d)?
strojnjashka [21]
"<span>The current is the same at all points" is the one among the following choices given in the question that answers the question correctly. The correct option among all the options that are given in the question is the fifth option or the last option. I hope that this is the answer that has come to your desired help.</span>
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Find the coefficient of kinetic friction μk. express your answer in terms of some or all of the variables d1, d2, and θ.
Andre45 [30]
<span>internet tension = mass * acceleration internet tension = 23 – Friction tension = 14 * acceleration Friction tension = µ * 14 * 9.8 = µ * 137.2 23 – µ * 137.2 = 14 * acceleration Distance = undemanding speed * time undemanding speed = ½ * (preliminary speed + very final speed) Distance = ½ * (preliminary speed + very final speed) * time Distance = 8.a million m, preliminary speed = 0 m/s, very final speed = a million.8 m/s 8.a million = ½ * (0 + a million.8) * t Time = 8.a million ÷ 0.9 = 9 seconds Acceleration = (very final speed – preliminary speed) ÷ time Acceleration = (a million.8 – 0) ÷ 9 = 0.2 m/s^2 23 – µ * 137.2 = 14 * 0.2 resolve for µ</span>
6 0
3 years ago
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What are the stages of agriculture
mixas84 [53]

Answer:

do you mean stages or branches

7 0
3 years ago
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How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?
Norma-Jean [14]
<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

  • Power of the engine as 400 watts
  • Force as 100 N
  • Distance the object is lifted up as 80 m

We are required to determine the time taken.

  • We need to know that power is the rate of work done

Therefore;

  • Power = Work done ÷ time

But, work done  = Force × distance

  • Therefore; In this case;

Work done = 100 N × 80 m

                  = 8000 Joules

  • Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

       = 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

4 0
3 years ago
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