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DENIUS [597]
3 years ago
11

Car A, moving in a straight line at a constant speed of 20. meters per second, is initially 200 meters behind car B, moving in t

he same straight line at a constant speed of 15 meters per second. How far must car A travel from this initial position before it catches up with car
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0
First, let's express the movement of Car A and B in terms of their position over time (relative to car B)
For car A: y=20x-200   Car A moves 20 meters every second x, and starts 200 meters behind car B
For Car B: y= 15x      Car B moves 15 meters every second and starts at our basis point

Set the two equations equal to one another to find the time x at which they meet:
20x - 200 = 15x
200 = 5x 
x= 40
At time x=40 seconds, the cars meet. How far will Car A have traveled at this time? 
Car A moves 20 meters every second:
20 x 40 = 800 meters
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Answer:

Isabella will not be able to spray Ferdinand.

Explanation:

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t = 0.45 s

Next, we shall determine the horizontal distance travelled by the water. This can be obtained as follow:

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s = 1.58 m

Finally, we shall compare the distance travelled by the water and the position to which Ferdinand is located to see if they are the same or not. This is illustrated below:

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From the above, we can see that the position of the water (i.e 1.58 m) and that of Ferdinand (i.e 10 m) are not the same. Thus, Isabella will not be able to spray Ferdinand.

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