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kirza4 [7]
3 years ago
7

Average velocity is different than average speed because calculating average velocity involves

Physics
1 answer:
borishaifa [10]3 years ago
6 0

Answer:

average velocity include total displacement whereas average speed include total distance

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D. It can be seen by the eye. I took this test. Hope this helped!

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A baseball is thrown a velocity of 20 m/s. It takes the 20 kg ball 10 seconds 5 points
liberstina [14]

Answer: 40 Newton

Explanation:

Mass of baseball = 20 kg

Velocity of baseball = 20 m/s.

Time taken for throwing = 10 seconds

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = velocity / time taken

Acceleration = (20 m/s / 10seconds)

Acceleration = 2m/s^2

Now, force required to throw the baseball is a product of mass and acceleration

i.e Force = Mass x acceleration

Force = 20 kg x 2m/s^2

Force = 40Newton

Thus, 40 newton of force is required to throw baseball to reach the plate

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3 years ago
What information does a free-body diagram show?
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4 years ago
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you push with an 18-N horizontal force on a 5-kg box of coffee resting on a on a horizontal surface. the force of friction on th
KatRina [158]

The acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

Answer:

Explanation:

As per Newton's second law of motion, acceleration of any object is directly proportional to the net external unbalanced force acting on that object and inversely proportional to the mass of the object.

Since there are two forces acting on the box in opposite direction, the net force will be the difference of horizontal and frictional force acting on the object.

Net force = Horizontal force - Frictional force = 18 N - 8 N = 10 N.

Now, from second law of motion, Acceleration = \frac{Net force}{Mass}

So, acceleration = 10 N /5 kg = 2 m/s².

Since, acceleration exerted by the box is found to be 2 m/s², we can determine the final velocity of the object after 10 seconds using the first equation of motion.

v = u + at, Here v is the final velocity and u is the initial velocity which is zero for the present case. Other parameters like a is found to be 2 m/s² and time is 10 seconds.

So Final velocity v = 0+(2×10)=20 m/s.

And the final position can be determined using the second equation of motion.

s = ut+1/2at²

Final position = (0×10)+(0.5×2×10×10)= 100 m.

So the final position is 100 m.

Thus, the acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

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3 years ago
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