Answer:
<h3>The answer is 1200 kg</h3>
Explanation:
The mass of an object can be found by using the formula

f is the force
a is the acceleration
From the question we have

We have the final answer as
<h3>1200 kg</h3>
Hope this helps you
Answer:
= 4.3 × 10 ⁻¹⁴ m
Explanation:
The alpha particle will be deflected when its kinetic energy is equal to the potential energy
Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C
Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C
Kinetic energy of the alpha particle = 5.28 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV)
= 8.459 × 10⁻¹³
k electrostatic force constant = 9 × 10⁹ N.m²/c²
Kinetic energy = potential energy = k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus
r = ( 9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 8.459 × 10⁻¹³
= 4.3 × 10 ⁻¹⁴ m
Explanation:
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Answer:
Explanation:
a. Given that:
mass of first & second piece,
mass of 3rd piece,
-velocity of first piece(
) and
as velocity of 2nd piece (
)
Let
be velocity of 3rd piece=?
#Vessel is at rest before explosion. Considering conservation of linear momentum:
#Dividing both sides by 

#Plug the
values:

#So the magnitude of the third piece is:

Magnitude of the 3rd piece is 10.84 m/s
b. To find direction of the magnitude (as an angle relative to the
-axis), we find
. The angle is obtained by getting the tan inverse as:

-The direction of the magnitude (angle relative to the x-axis) is 45°
Answer:
Explanation:
Using Pascal laws, which states that pressure are the input equals the pressure at the output.
Pressure is given as force/area
P1=P2
Then,
F1/A1=F2/A2
Cross multiply
F1A2=F2A1
Given that
Ae=0.5m² area of effort
Al=5m² area of load
Fl=? Force if load
Fe= 100N. Force of effort
Then applying pascal
Fl/Al=Fe/Ae
Fl/5=100/0.5
FL/5=200
Fl=200×5
Fl=1000N
The first safety load is 1000N