Ask question

Ask question

All categories

jek_recluse [69]

3 years ago

15

Airbrakes on some trucks have how many second lag time with for the engage properly?

1 answer:

olga2289 [7]3 years ago

6 0

The answer that best completes the given statement above is ONE SECOND (1). There should only be one second of lag time to engage properly for some of the airbrakes of the trucks. One half to one second is the normal lag time and it should not exceed beyond this time. Hope this helps.

You might be interested in

What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= ac

Pachacha [2.7K]

<span>GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J</span>

6 0

3 years ago

The graph shows the federal budget from 1980 to 2010. In which period did the federal budget show the greatest deficit?

kodGreya [7K]

Answer:

2000 to 2010

Explanation:

sorry I'm just guessing

8 0

2 years ago

A shot is projected at an angle of 55 to the horizontal with a velocity of of 10m/s. Calculate 1. the highest point reached 2. T

il63 [147K]

Answer:

my gess g=10m/s

Explanation:

5 0

2 years ago

a car goes from a velocity zero to a velocity of 15 meters per second East in 2.1 seconds. What is the car's acceleration?

leva [86]

31.5 would be the acceleration.

3 0

3 years ago

A hot-air balloon and its basket are accelerating upward at 0.265 m/s2, propelled by a net upward force of 688 N. A rope of negl

Sergeu [11.5K]

Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>

Answer:

The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.

Explanation:

Let us call the mass of the balloon $m_1$ and the mass of the basket $m_2$ , then according to newton's second law:

$(1). \:F = (m_1+m_2)a$ ,

where $a =0.265m/s^2$ is the upward acceleration, and $F = 688N$ is the net propelling force (counts the gravitational force).

Also, the tension $T$ in the rope is 79.8 N more than the basket's weight; therefore,

$(2). \:T = m_2g+79.8$

and this tension must equal

$T -m_2g =m_2a$

$(3). \:T = m_2g +m_2a$

Combining equations (2) and (3) we get:

$m_2a = 79.8$

since $a =0.265m/s^2$ , we have

$\boxed{m_2 = 301.13kg}$

Putting this into equation (1) and substituting the numerical values of $F$ and $a$ , we get:

$688N = (m_1+301.13kg)(0.265m/s^2)$

$\boxed{m_1 = 2295 kg}$

Thus, the mass of the balloon and the basket is 2295 kg and 301 kg respectively.

8 0

3 years ago