Answer:
Explanation:
Given that,
Radius of a spherical shell, r = 0.7 m
Torque acting on the shell,
Angular acceleration of the shell,
We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :
I is the rotational inertia of the shell
So, the rotational inertia of the shell is .
Answer:
L=55.9m
Explanation:
The equation for the period of a simple pendulum is:
In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:
Which for our values is:
Answer:
448 J/kg/°C
Explanation:
m₁ C₁ (T₁ − T) + m₂ C₂ (T₂ − T) = 0
(0.0414 kg) C (243°C − 20.4°C) + (0.411 kg) (4186 J/kg/°C) (18°C − 20.4°C) = 0
(9.22 kg°C) C − 4129 J = 0
C = 448 J/kg/°C
<span>here u go!
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