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iVinArrow [24]
3 years ago
6

In a group of 20 students, half have blue eyes, 10% have brown eyes, and the rest have hazel eyes. How many students have hazel

colored eyes?
Show me your work plz!
Mathematics
1 answer:
Ber [7]3 years ago
5 0
So you have 20 people and 10 percent have brown eyes. So if 100% is 20, to find 10 percent you divide it by 10 to get 10% is 2. You know all the rest have hazel eyes so you just do 20-2 to get 18. Therefore 18 people have hazel eyes. Hope this helps :)
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How do I solve 4/9+9/2 and write my answer as a mixed number?
jenyasd209 [6]

9 has factors of 3*3.

2 is prime, so no factors.

from those two denominators, we can get the LCD of hmmm simply their product, namely 18.

\bf \cfrac{4}{9}+\cfrac{9}{2}\implies \stackrel{\textit{using the LCD of 18}}{\cfrac{(2)4+(9)9}{18}}\implies \cfrac{8+81}{18}\implies \cfrac{89}{18}\implies 4\frac{17}{18}

now, recall that, to get the mixed fraction, we divide 89 ÷ 18, the quotient goes up front, the "4", and the remainder is the one atop, the "17".

8 0
3 years ago
What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D
Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

4 0
3 years ago
Combine like terms to simplify 3x + 3 + 3x + 8=
Over [174]

Answer:

6x + 11

Step-by-step explanation:

3x + 3 + 3x + 8

Combine like terms (terms with the same amount of variables).

3x + 3x + 3 + 8 =

(3x + 3x) + (3 + 8) =

6x + 11

6x + 11 is your answer.

~

3 0
3 years ago
Simplify the radical expression. Show all your steps. <br><br> √363 - 3√27
siniylev [52]

Answer:

2 sqrt(3)

Step-by-step explanation:

Simplify the following:

sqrt(363) - 3 sqrt(27)

sqrt(27) = sqrt(3^3) = 3 sqrt(3):

sqrt(363) - 33 sqrt(3)

sqrt(363) = sqrt(3×11^2) = 11 sqrt(3):

11 sqrt(3) - 3×3 sqrt(3)

-3×3 = -9:

11 sqrt(3) + -9 sqrt(3)

11 sqrt(3) - 9 sqrt(3) = 2 sqrt(3):

Answer: 2 sqrt(3)

3 0
3 years ago
The product of twice a number and six is the same as the difference of eleven times the number and 6/5 . Find the number
Rom4ik [11]

Answer:

-6/5

Step-by-step explanation:

solution;

let,the number be x,

product of <u>twice</u><u> </u><u>of</u><u> </u><u>x</u> and <u>six</u> = the <u>difference </u>

<u>difference of eleven times x and 6/5</u>

or, (2x×6)=(11×x)-(6/5)

or, 12x = 11x - 6/5

or, 12x - 11x = -6/5

therefore,x =-6/5

Therefore, the number required is (-6/5) whose product of twice a number and six is the same as the difference of eleven times the number and 6/5 .

3 0
3 years ago
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