2 years ago

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Chemistry

2 answers:

Citrus2011 [14]2 years ago

6 0

SURE why not i just need points sorry

OLga [1]2 years ago

5 0

Answer:

Will DO

Explanation:

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_Au2S3 + _H2---> _Au + _H2S

timofeeve [1]

The answer is A because if you place the first two numbers 1 and 3
Au=2
S=3
H=6
It has to equal to the product so then you put in the last two numbers 2 and 3
Au=2
S=3
H=6

4 0

2 years ago

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In order to get lots of helium into tanks to fill kiddy balloons, they put force or pressure onto it. If i have 595 liters of he

alexandr402 [8]

Answer:

1.90 L

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 595 L

V₂ = ?

P₁ = 1.00 atm

P₂ = 55.0 atm

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.00}\times {595}={55.0}\times {V_2}$

${V_2}=\frac{{1.00}\times {595}}{55.0}\ L$

${V_2}=1.90\ L$

<u>The volume would be 1.90 L.</u>

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2 years ago

What is the abbreviated electron configuration of cobalt?

drek231 [11]

It's Co just look at the periodic table

7 0

3 years ago

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Which of the following best describes Newton's Second Law of Motion? (more than one answer applies)

masya89 [10]

I need this answer too.

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2 years ago

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Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of

jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = $2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x$

$2330.35x=1048815\\x=450.068g$

Hence, there was 450.068g of water in the pot.

8 0

2 years ago

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