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2 years ago

WHAT CAN BE USED TO REPLACE OIL? help 30POINTS!!!!! ASAP

Chemistry

2 answers:

kkurt [141]2 years ago

8 0

Answer:

Melted butter

Explanation:

pashok25 [27]2 years ago

4 0

Answer:

Look below

Explanation:

The following may be substituted cup for cup for vegetable oil in baked goods:

Applesauce, preferably unsweetened.

Banana, ripe and mashed.

Butter, melted.

Cauliflower – unseasoned, cooked, and pureed.

Ghee.

Margarine, melted.

Mayonnaise.

Pumpkin, cooked and pureed.

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makvit [3.9K]

They are both made up of the same protein called "histones".

6 0

2 years ago

Read 2 more answers

What is the frequency of a radio wave with a a wavelength of 3 m? (Hint: MHz

Ostrovityanka [42]

Answer:
a. 1 x 10^8

Explanation:

100 MHz = 100,000,000 Hz = 10^8 Hz

4 0

1 year ago

6. A sample of a gas has a mass of 0.527 g. Its volume is 0.35 L at a temperature of 88 degree Celsius and a pressure of 945 mm

Stels [109]

<u>Answer:</u> The molar mass of the gas is 35.87 g/mol.

<u>Explanation:</u>

To calculate the mass of gas, we use the equation given by ideal gas:

PV = nRT

or,

$PV=\frac{m}{M}RT$

where,

P = Pressure of gas = 945 mmHg

V = Volume of the gas = 0.35 L

m = Mass of gas = 0.527 g

M = Molar mass of gas = ? g/mo

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

T = Temperature of gas = $88^oC=[88+273]=361K$

Putting values in above equation, we get:

$945mmHg\times 0.35L=\frac{0.527g}{M}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 361K\\\\M=35.87g/mol$

Hence, the molar mass of the gas is 35.87 g/mol.

5 0

3 years ago

4Fe (s) + 3 O2 (g) → 2 Fe2O3 (s)

Novay_Z [31]

Explanation:

The number acquired by an element after the lose or gain of an electron is called oxidation number.

For example, $4Fe(s) + 3O_{2}(g) \rightarrow 2Fe_{2}O_{3}(s)$

Here, oxidation number of Fe(s) is 0 and Fe in $Fe_{2}O_{3}$ is +3.

Oxidation number of O in $O_{2}(g)$ is 0 as it is present in its elemental state.

The oxidation number of O in $Fe_{2}O_{3}$ is calculated as follows.

$2(3) + 3x = 0\\6 + 3x = 0\\x = \frac{-6}{3}\\= -2$

Hence, oxidation number of O in $Fe_{2}O_{3}$ is -2.

The loss of electrons by an element or substance is called oxidation. Here, electrons are being lost by Fe(s) as an increase in oxidation state is occurring. So, Fe(s) is oxidized.

The gain of electrons by an element or substance is called reduction. Here, electrons are being added to $O_{2}$ as a decrease in its oxidation state is occurring. So, $O_{2}$ is reduced.

An element or compound which is being reduced is called oxidizing agent. Here, $O_{2}$ is the oxidizing agent.

An element or compound which is being oxidized is called reducing agent. Here, Fe(s) is the reducing agent.

5 0

3 years ago

A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulated container at 1 bar. Calculate the tempe

Deffense [45]

Answer:

The temperature of the system once the equilibrium has been reached = 372.55K

Explanation:

Heat capacity of gold = 129 J/Kg*c.

Heat capacity of water

4,184 J/Kg*c.

Mass of gold = 75g = 0.075Kg

Mass of water = 200g = 0.2Kg

From conservation of energy

m1×C1×(t11 - t2) = m2×C2×(t2- t21)

Substituting we have

0.075 × 129×(1000-t2) = 0.2× 4184×( t2 -300) =solving for t2, we have

933.55×t2 = 347790

or t2 = 372.55K

The temperature of the system once the equilibrium has been reached = 372.55K

6 0

3 years ago