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KatRina [158]
3 years ago
10

What is the molar mass of Ca(NO3)2?

Chemistry
1 answer:
gregori [183]3 years ago
7 0

Answer:

C.164.1g/mol

Explanation:

40+14×2+16×6

164

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The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat
user100 [1]

<u>Answer:</u> The heat required for the process is 4.24 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of benzene = 24.8 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

\text{Moles of benzene}=\frac{24.8g}{78.11g/mol}=0.318mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = ?

n = number of moles = 0.318 moles

\Delta H_{rxn} = enthalpy change of the reaction  = 30.7 kJ/mol

Putting values in above equation, we get:

30.7kJ/mol=\frac{q}{0.318mol}\\\\q=(30.7kJ/mol\times 0.318mol)=4.24kJ

Hence, the heat required for the process is 4.24 kJ

6 0
3 years ago
If a car travels 400.0 meters in 20.0 seconds, how fast is it going?<br> m/s<br> Please help me
Viefleur [7K]

Answer:

20m/s.

Explanation:

8 0
3 years ago
What is the total mass of solute in 1000. grams of a solution having a concentration of 5 parts per million?
Art [367]

50 grams or 50,000 mili grams  is the mass of solute in 1000 grams of a solution having a concentration of 5 parts per million.

Explanation:

Total mass of solution = 1000 grams or 1000 ml since 1 gram = 1 ml

concentration is 5 parts per million ( 5 mg in 1000 ml solution or 0.005 gram in 1000 ml)

the formula used for parts per million:

parts per million = \frac{mass of solute (mg)}{volume of solution}

putting the values in the equation:

parts per million = \frac{mass of solute}{volume of solvent}

0.005 x 1000 = mass of solute

50 grams= mass of solute

converting this into mg

50,000 mg. is the total mass of solute in 5ppm of 1000 ml solution.

4 0
4 years ago
What is the new concentration of 25.0mL added to 125.0mL of 0.150M
____ [38]

Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

M₂ = 18.75 M.mL/150 mL

M₂ = 0.125 M

The new concentration is 0.125 M.

8 0
3 years ago
How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
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