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stiv31 [10]
3 years ago
15

What is the radius of the event horizon for a black hole with a mass 7.5 times the mass of the sun? This distance is called the

Schwarzschild radius. Express your answer with the appropriate units.
Physics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

1.1\times10^{4}m

Explanation:

The Schwarzschild radius can be calculated as follows:

R=\frac{GM}{c^2}

Where, <em>G</em> is the gravitational constant, <em>M</em> is the mass and <em>c</em> is the speed of light.

Mass of sun is 1.98×10³⁰ kg

R=\frac{G\times 7.5M_{sun}}{c^2}\\ R=\frac{6.67\times10^{-11}\times(7.5\times1.98\times10^{30})}{(3\times10^8)^2}\\ \Rightarrow R=1.1\times10^{4}m

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Optical astronomers need a clear, dark sky to collect good data. Explain why radio astronomers have no problem observing in the
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In the clarification portion elsewhere here, the definition of the concern is mentioned.

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3 years ago
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A) An automobile light has a 1.0-A current when it is connected to a 12-V battery. Determine the resistance of the light.
kirill [66]

Answer:

The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

Explanation:

Given:

(A)

Current I = 1 A

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  V = IR

  R = \frac{V}{I}

  R = \frac{12}{1}

  R = 12Ω

(B)

For finding power delivered,

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  P = (1) ^{2} \times 12

  P = 12 Watt

(C)

For finding the potential difference,

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Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V

4 0
3 years ago
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