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stiv31 [10]
3 years ago
15

What is the radius of the event horizon for a black hole with a mass 7.5 times the mass of the sun? This distance is called the

Schwarzschild radius. Express your answer with the appropriate units.
Physics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

1.1\times10^{4}m

Explanation:

The Schwarzschild radius can be calculated as follows:

R=\frac{GM}{c^2}

Where, <em>G</em> is the gravitational constant, <em>M</em> is the mass and <em>c</em> is the speed of light.

Mass of sun is 1.98×10³⁰ kg

R=\frac{G\times 7.5M_{sun}}{c^2}\\ R=\frac{6.67\times10^{-11}\times(7.5\times1.98\times10^{30})}{(3\times10^8)^2}\\ \Rightarrow R=1.1\times10^{4}m

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In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole.
Fiesta28 [93]

Answer:

6.0 m/s

Explanation:

According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.

Therefore, we can write:

KE_i+PE_i =KE_f+PE_f

or

\frac{1}{2}mu^2+0=\frac{1}{2}mv^2+mgh

where:

m is the mass of the athlete

u is the initial speed of the athlete (at the bottom)

0 is the initial potential energy of the athlete (at the bottom)

v = 0.80 m/s is the final speed of the athlete (at the top)

g=9.8 m/s^2 is the acceleration due to gravity

h = 1.80 m is the final height of the athlete (at the top)

Solving the equation for u, we find the initial speed at which the athlete must jump:

u=\sqrt{v^2+2gh}=\sqrt{0.80^2+2(9.8)(1.80)}=6.0 m/s

4 0
3 years ago
Out of aluminum,copper,steel,and glass.Which material do you think will be the best thermal conductor?
Nastasia [14]
I believe it is copper

6 0
3 years ago
The vertical columns in the periodic table are called _____________. families periods rows
bonufazy [111]

Answer:

families

Explanation:

periods are horizontal

4 0
3 years ago
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Two disks of polaroid are aligned so that they polarize light in the same plane. Calculate the angle through which one sheet nee
Olegator [25]

Answer: The unpolarized light's intensity is reduced by the factor of two when it passes through the polaroid and becomes linearly polarized in the plane of the Polaroid. When the polarized light passes through the polaroid with the plane of polarization at an angle \theta with respect to the polarization plane of the incoming light, the light's intensity is reduced by the factor of \cos^2\theta (this is the Law of Malus).

Explanation: Let us say we have a beam of unpolarized light of intensity I_0 that passes through two parallel Polaroid discs with the angle of \theta between their planes of polarization. We are asked to find \theta such that the intensity of the outgoing beam is I_2. To solve this we follow the steps below:

Step 1. It is known that when the unpolarized light passes through a polaroid its intensity is reduced by the factor of two, meaning that the intensity of the beam passing through the first polaroid is

I_1=\frac{I_0}{2}.

This beam also becomes polarized in the plane of the first polaroid.

Step 2. Now the polarized beam hits the surface of the second polaroid whose polarization plane is at an angle \theta with respect to the plane of the polarization of the beam. After passing through the polaroid, the beam remains polarized but in the plane of the second polaroid and its intensity is reduced, according to the Law of Malus, by the factor of \cos^2\theta. This yields I_2=I_1\cos^2\theta. Substituting from the previous step we get

I_2=\frac{I_0}{2}\cos^2\theta

yielding

\frac{2I_2}{I_0}=\cos^2\theta

and finally,

\theta=\arccos\sqrt{\frac{2I_2}{I_0}}

3 0
3 years ago
A glass of water with a mass of 0.35 kg rests on the edge of a desk 0.85 m
ivolga24 [154]

Answer:it’s c

Explanation:

Just is

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