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AlexFokin [52]
3 years ago
12

what is cut off from the open sea coral reefs or sandbars A watershed B lagoon C reef or D atoll . also this is a science questi

on but i could not find science on here so i chose physics

Physics
2 answers:
Klio2033 [76]3 years ago
7 0
Hello there.

Its D.

HOPE I HELPED

Igoryamba3 years ago
4 0

Answer:

Option (B)

Explanation:

A lagoon is defined as a shallow water body that is often separated by a larger water body such as oceans by a coral reef or sandbars. This lagoons are of 2 types, namely the coastal lagoon and the atoll lagoon.

(1) Coastal lagoon-This type of lagoons are protected by sandbars or barrier islands. They usually form along coastal areas with small range in the tidal. They are shallow type of basin that are present near the gradually eroding shore.

(2)Atoll lagoon- They are almost similar to the coastal lagoons, but they are mostly protected by the coral reefs. These are commonly found in the oceans of tropical regions.

Thus, the correct answer is option (B).

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How to find acceleration in non uniform motion. Please give two ways
Olenka [21]

<u>The two ways to  find acceleration in non uniform motion are as follows:</u>

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<u>Explanation:</u>

Non-uniform acceleration comprises the most common description of motion. Acceleration refers to the rate of changes of velocity per unit time. Basically, it implies that acceleration changes during motion. This variety can be communicated either as far as position (x) or time (t).

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Calculus analysis is general and accurate, but limited to the availability of speed and acceleration expressions. It is not always possible to get the expression of motion attributes in the form "x" or "t". On the other hand, the graphic method is not accurate enough, but it can be used accurately if the graphic has the correct shapes.

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3 years ago
What will happen to the mass and volume of a block if their is two blocks, three, blocks or four blocks? For example, if the mas
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For a particular casting setup, the top of the sprue has a diameter of 0.030 m, and its length is 0.200 m. The volume flow rate
faust18 [17]

Answer with Explanation:

We are given that

Diameter=0.030 m

Length of sprue=h_1=0.200 m

Metal volume flow  rate,Q=0.03m^3/min

Q=\frac{0.03}{60}=5\times 10^{-4}m^3/s because 1 minute=60 seconds

Let 1 for the top and 2 for the bottom

d_=0.030 m

h_2=0

A_1=\frac{\pi d^2}{4}=\frac{3.14\times (0.030)^2}{4}

A_1=7.065\times 10^{-4} m^2

v_1=\frac{Q}{A_1}=\frac{5\times 10^{-4}}{7.065\times 10^{-4}}

v_1=0.708 m/s

Pressure at the top and bottom of the sprue is atmospheric

h_1+\frac{v^2_1}{2g}=h_2+\frac{v^2_2}{2g}

Substitute the values

0.2+\frac{(0.708)^2}{2\cdot 9.8}=0+\frac[v^2_2}{2\cdot 9.8}

v^2_2=2\cdot 9.8\cdot \frac{0.2\cdot 9.8\cdot 2+0.501264}{2\cdot 9.8}=4.421264

v_2=\sqrt{4.421264}=2.1 m/s

Q=A_2v_2

5\times 10^{-4}=A_2\times 2.1

A_2=\frac{5\times 10^{-4}}{2.1}=2.381\times 10^{-4} m^2

Reynolds number=\frac{v_2D\rho}{\eta}

\eta=0.004 N.s/m^2

\rho=2700 kg/m^3

Substitute the values then we get

Reynolds number=\frac{2.1\times 0.03\times 2700}{0.004}

Reynolds number=42525

The Reynolds number is greater than 4000 .Therefore, the flow is turbulent.

8 0
3 years ago
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