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3 years ago

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what velocity must a 1340kg car have in order to havw the same momentum as a 2680 kg truck traveling at a velocity of 15m/s to t

he west?

1 answer:

kykrilka [37]3 years ago

6 0

Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.

Hope i helped
Have a good day :)

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Explanation:

The given data is as follows.

Dielectric constant, K = 3.0

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Distance between plates (d) = $2.75 \times 10^{-3} m$

Maximum electric field (E) = $3.25 \times 10^{5} V/m$

Now, we will calculate the capacitance as follows.

C = $\frac{k \epsilon_{o} \times A}{d}$

= $\frac{3.0 \times 8.85 \times 10^{-12} \times 0.021}{2.75 \times 10^{-3}}$

= $\frac{0.55755 \times 10^{-12}}{2.75 \times 10^{-3}}$

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Formula to calculate electric charge is as follows.

E = $\frac{\sigma}{k \epsilon_{o}}$

or, Q = $E \times k \times \epsilon_{o}A$ (as $\frac{\sigma}{\epsilon_{o}} = \frac{Q}{A}$ )

= $3.25 \times 10^{5} \times 3.0 \times 8.85 \times 10^{-12} \times 0.021$

= $181.2 \times 10^{-9} C$

Formula to calculate the energy is as follows.

U = $\frac{1 \times Q^{2}}{2 \times C}$

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= $9835.67 \times 10^{-9}$

or, = $98.35 \times 10^{-7} J$

Thus, we can conclude that the maximum energy that can be stored in the capacitor is $98.35 \times 10^{-7} J$ .

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