1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anarel [89]
3 years ago
12

what velocity must a 1340kg car have in order to havw the same momentum as a 2680 kg truck traveling at a velocity of 15m/s to t

he west?
Physics
1 answer:
kykrilka [37]3 years ago
6 0
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.

Hope i helped
Have a good day :)

 
You might be interested in
A graduated cylinder.measures 15.3 mL. Convert this measurement to DaL
ololo11 [35]

Answer:

0.000153DaL  

Explanation:

We have been given:

         15.3mL to convert to DaL

DaL is a unit of volume which indicates a decaliter.

 This implies that;

             1 Da L  = 1 x 10²L

So:

               1 mL  = 1 x 10⁻³L

       So 15.3mL will give 15.3 x 10⁻³L

So;

           1 x 10²L   =  1 DaL  

      15.3 x 10⁻³L  will give \frac{15.3 x 10^{-3} }{1 x 10^{2} }   = 15.3 x 10⁻⁵DaL

Therefore, this is 0.000153DaL  

           

5 0
3 years ago
What is 9.7e-6 as a decimal
skelet666 [1.2K]

Answer:

See below

Explanation:

9.7e-6     is     9.7 x 10^-6      move the decimal 6 to the LEFT to get

                      =  .0000097

4 0
2 years ago
One end of a horizontal spring with force constant 130.0 N/m is attached to a vertical wall. A 3.00 kg block sitting on the floo
Nuetrik [128]

Answer:

a) v = 0

b) The aceleration is 1.41 m/s^{2}

c) The block is accelerating away from the wall.

Explanation:

First, you need to think about the effect this constant force is causing in the spring: it causes a displacement in the equilibrium point of the system, therefore we need to know where it sits now:

At equilibrium no movement is present reducing friction to 0:

\sum{F} = 0 = F_{spring} - F_{external}

F_{spring} = F_{external}

Kx = F_{external}

x = \frac{F_{external}}{K}=\frac{88}{130}=0.68m=68cm

This means that the spring can be compressed with the single force up to 68 cm, Any further compression will cause an unbalanced system and the occilation of the mass.

The spring can't be compressed by the given force to 80 cm, therefore it must have been compressed by another force and then released.

In this case, the instantanous speed is 0, since the block has just been released.

In the same instant we can stimate the free body diagram of forces by the next two equations:

\sum_y{F}={F_N-W}=0\\\sum_x{F}={F_{spring}-F_{external}-F_{friction}}=ma

For the y axis:

F_N = W = mg = 3*9.8 = 29.4N

To calculate the force of friction:

F_{friction} = \mu_k F_N=0.4*29.4 = 11.76N

Therefore for x axis:

{Kx-F_{external}-F_{friction}}=ma

a = \frac{130*0.8-88-11.76}{3} = \frac{104-88-11.76}{3}=\frac{4.24}{3}=1.41\frac{m}{s^2}

7 0
3 years ago
The slope of a displacement vs. time graph gives
Sauron [17]
The answer is b. Velocity
3 0
3 years ago
If the force of gravity between a book of mass 0.50 kg and a calculator of 0.100 kg is 1.5 × 10-10 N, how far apart are they?  (
valkas [14]
The gravitational force between two masses m₁ and m₂ is
F=G \frac{m_{1} m_{2}}{d^{2}}
where
G = 6.67408 x 10⁻¹¹ m³/(kg-s²), the gravitational constant
d =  distance between the masses.

Given:
F = 1.5 x 10⁻¹⁰ N
m₁ = 0.50 kg
m₂ = 0.1 kg

Therefore
1.5 x 10⁻¹⁰ N = (6.67408 x 10⁻¹¹ m³/(kg-s²))*[(0.5*0.1)/(d m)²]
d² = [(6.67408x10⁻¹¹)*(0.5*0.1)]/1.5x10⁻¹⁰
     = 0.0222
d = 0.1492 m = 149.2 mm

Answer: 149.2 mm
8 0
4 years ago
Other questions:
  • How long does it take a wave to travel 1200 meters with the speed of 3 X 108m/sec?
    8·1 answer
  • A worker leaves home at 9:00 AM, travels 40 km to the office, and then returns home at 5:00 PM. What is the magnitude of the wor
    15·2 answers
  • A circular sign has a diameter of 40 cm and is subjected to normal winds up to 150 km/h at 10°C and 100 kPa. Determine the drag
    9·1 answer
  • A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the locomotive moved 12.0 m [E] in 10.0 s. a. Det
    13·1 answer
  • A 26.3 kg object is traveling at 21.0 m/s north. What average net force is required to bring this object to a stop in 2.60 secon
    13·1 answer
  • A 0.030-m3 container is initially evacuated. Then, 4.0 g of water is placed in the container, and, after some time, all the wate
    11·1 answer
  • The momentum of blue whale with a mass of 146,000 kg and a top swimming speed of 24 km/hr is kg·m/s.
    14·1 answer
  • Which of the following is NOT an indicator of a physical change?
    7·1 answer
  • 3. One effective method for coping with change is using:
    14·1 answer
  • Read the passage.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!