Question

Use the conversion factors to rewrite the distances in different, but equivalent, units.

Answer 1

0.57633322 is the answer for 2

Answer 2

Explanation:

1 pc = 206265 AU

$1 AU = 1.496\times 10^{8} km$

Distance of an object A from the sun = 0.000001877 pc

$0.000001877 pc=0.000001877\times 206265 AU=0.387159405 AU$

$0.387159405 AU=0.387159405\times 1.496\times 10^{8} km=5.7919\times 10^7 km$

$0.000001877 pc=5.7919\times 10^7 km$

Distance of an object B from the sun = 30.06 AU

$30.06AU=30.06\times 1.496\times 10^{8} km=4.497\times 10^{9} km$

Distance of an object C from the sun = 778.3 million km

1 million km = $10^6 km$

$778.3 \text{million km}=778.3\times 10^6 km=7.783\times 10^8 km$