6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
More than 10 a gumball.
150 divided by 15 is 10, which would be the price you bought for. If you want to make more money, you must at least have a surge pricing of 10 unit prices per gumball.
Answer:
None of the above
Step-by-step explanation:
x-1/3 = k
We know that k=3, so we can substitute that into the equation
x-1/3 = 3
Add 1/3 to each side
x-1/3 + 1/3 = 3+1/3
x = 3 1/3 or as an improper fraction 10/3
Answer:
x =0
Step-by-step explanation:
4+5e^x+2 =11
Combine like terms
6 + 5e^x =11
Subtract 6 from each side
6-6 + 5e^x =11-6
5 e^x = 5
Divide by 5 on each side
5 e^x /5 = 5/5
e^x = 1
Take the natural log on each side
ln (e^x) = ln(1)
x = ln(1)
x =0
There is no picture for me to check
