Ask question

Ask question

All categories

3 years ago

13

Vector e is 0.111m long in a 90 deg direction. Vector f is 0.233 m long in 400 deg direction. Find the direction of their vector

sum

1 answer:

-BARSIC- [3]3 years ago

7 0

Answer:

50.6

Explanation:

You might be interested in

Only answer if you would send your eggplant

Mariulka [41]

Answer:

yup

Explanation:

8 0

3 years ago

Identify the action and reaction forces in the following situations: a) Earth attracts the Moon, b) a boy kicks a football, c) a

jeka94

Answer:

#See solution for details

Explanation:

a. Action: Earth pulls on the Moon, reaction: Moon pulls on Earth;

b. Action: foot applies force to ball, reaction: ball applies force to foot;

c. Action: rocket pushes on gas, reaction: gas pushes back on rocket;

d. Action: car tires push backward on road, reaction: road pushes forward on tires;

e. Action: jumper pushes down on ground, reaction: ground pushes up on jumper;

f. Action: gun pushes forward on bullet, reaction: bullet pushes backward on gun

7 0

3 years ago

What is electromagnetic indiction

lora16 [44]

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field. Michael Faraday is generally credited with the discovery of induction in 1831, and James Clerk Maxwell mathematically described it as Faraday's law of induction.

6 0

3 years ago

A particular field is 111 yards long. Express this length in meters.

romanna [79]

Answer:

101.498 m

Explanation:

8 0

3 years ago

Read 2 more answers

Coherent light of wavelength 525 nm passes through two thin slits that are 4.15Ã—10^(âˆ’2) mm apart and then falls on a screen 7

IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

$sin \theta=\frac{n \lambda}{d}$

where

n is the order of the maximum

$\lambda$ is the wavelength

$a$ is the distance between the slits

In this problem,

n = 5

$\lambda=525 nm =5.25\cdot 10^{-7} m$

$a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m$

So we find

$\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}$

And given the distance of the screen from the slits,

$D=75.0 cm = 0.75 m$

The distance of the 5th bright fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm$

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

$sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}$

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

$\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}$

And the distance of the 8th dark fringe from the central bright fringe will be given by

$y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm$

5 0

3 years ago