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lesya692 [45]
3 years ago
10

To determine if an object is in motion, you must use a __________. Question 1 options: Moving object Living thing Frame of Refer

ence Larger object
Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer: moving object :)

Explanation:

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Why is it possible to see yourself in a object that reflects light, but not in one that scatters light
dedylja [7]
I think it is because in objects that reflect light, the light is bounces/reflects off the object in one direction and one angle, and hits your eye, causing it to be processed as a reflection of yourself in your brain. But in one that scatters light, it bounces/reflects off in many different directions. Due to this, your brain may not process it as a reflection.
Here is a little bit of extra info:
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3 years ago
Transistor heating up in tesla coil !!!! please help me.
svetoff [14.1K]

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7 0
3 years ago
photon strikes the surface of tungsten and an electron is emitted. what is the maximum possible speed of the electron?
zalisa [80]

Answer: The maximum possible speed v is √2(  hν - Ф  ) / m

Explanation: You could be referring to the provided explanation, despite the fact that the question isn't comprehensive. When a photon collides with the surface of any metal, it transmits all of its energy to the electron in the atom. The collision causes the electron to travel with a certain amount of kinetic energy. This is referred to as the photoelectric effect. The maximum kinetic energy is calculated using Einstein's equation for the photoelectric effect:

K.E. = hν - Ф

½ mv² = hν - Ф

Hence the maximum possible speed is:

v = √2(  hν - Ф  ) / m

For more information on the photoelectric effect refer to this link: brainly.com/question/25027428

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3 0
2 years ago
a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&
Katen [24]

Answer:

a)  T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

        sin 30 = \frac{T_x}{T}

        cos 30 = \frac{T_y}{T}

        Tₓ = T sin 30

        T_y = T cos 30

Y axis  

       T_y -W = 0

       T cos 30 = mg                     (1)

X axis

        Tₓ = m a

they relate it is centripetal

        a = v² / r

we substitute

         T sin 30 = m\frac{v^2}{r}            (2)

a) we substitute in 1

         T = \frac{mg }{cos 30}

         T = \frac{ 0.2 \ 9.8}{cos  \ 30}

         T = 2.26 N

b) from equation 2

           v² = \frac{T \ sin 30 \ r}{m}

If we know the length of the string

          sin 30 = r / L

          r = L sin 30

we substitute

          v² = \frac{ T \ sin 30 \ L \ sin 30}{m}

          v² = \frac{TL \ sin^2  30}{m}

For the problem let us take L = 1 m

let's calculate

          v = \sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }

          v = 1.68 m / s

8 0
3 years ago
A 0.50-kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it i
NeTakaya

The impulse given to the ball is equal to the change in its momentum:

J = ∆p = (0.50 kg) (5.6 m/s - 0) = 2.8 kg•m/s

This is also equal to the product of the average force and the time interval ∆t :

J = F(ave) ∆t

so that if F(ave) = 200 N, then

∆t = J / F(ave) = (2.8 kg•m/s) / (200 N) = 0.014 s

7 0
2 years ago
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