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Chemistry

2 answers:

ololo11 [35]2 years ago

8 0

Third choice because the others make no sense

erik [133]2 years ago

5 0

Answer: It is a salt because it is formed by the reaction of an acid and a base.

Explanation: When an Acid and Base reacts with each other, the product formed is known as Salt. This reaction is a kind of neutralization reaction in which acid is being neutralized by the base.

Thus Sodium Chloride is a salt because it is formed by the neutralization reaction of the strong acid like HCl and strong base like NaOH

HCl(aq) + NaOH (s) → NaCl(s)

Thus all the other options given are wrong.

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If a reaction mixture contains 24 g of Mg and 32 g of O2 , what is the limiting reactant?

Alexxx [7]

This problem is providing the mass of both magnesium metal and oxygen gas and involved in a chemical reaction and asks for the limiting reactant. At the end, it turns out to be identified as magnesium.

<h3>Stoichiometry</h3>

In chemistry, stoichiometry is a widely-used tool we use in order to relate the mass and moles of different chemical substances involved in a chemical reaction. Thus, we consider the following chemical equation between magnesium and oxygen to produce magnesium oxide.

$2Mg+O_2\rightarrow 2MgO$

However, when the mass of the both of the reactants is given, one must identify the limiting reactant as the one producing the least of the moles of the product, which means we can use the given grams of the both of the reactants, their molar masses and mole ratios with the product to obtain the aforementioned:

$24gMg*\frac{1molMg}{24.3gMg}*\frac{2molMgO}{2molMg}=0.988molMgO\\ \\ 32gO_2*\frac{1molO_2}{32.0gO_2}*\frac{2molMgO}{1molO_2}=2molMgO$

Thus, we can evidence how 24 g of magnesium produce the least of the moles of magnesium oxide, fact validating the magnesium as the limiting reactant and the oxygen as the excess one.