Answer:
The pH of the resulting solution is 9.02.
Explanation:
The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:
![pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})](https://tex.z-dn.net/?f=%20pOH%20%3D%20pKb%20%2B%20log%28%5Cfrac%7B%5BNH_%7B4%7DCl%5D%7D%7B%5BNH_%7B3%7D%5D%7D%29%20)
Now, the perchloric acid added will react with ammonia:
Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:
NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O
Finally, we can calculate the pH of the resulting solution:
Therefore, the pH of the resulting solution is 9.02.
I hope it helps you!
Answer:
(a). 132 × 10^-9 s = 132 nanoseconds.
(b)..176.5 pico-seconds.
Explanation:
(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;
Speed = [ (8 × R × T)/ Mm × π]^1/2.
Where Mm = molar mass, T = temperature and R = gas constant.
Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.
The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;
Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.
Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.
Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.
Degree of collision = 7.55 × 10^6 s^-1.
Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.
(b). At one bar;
1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.
Answer:
refer attachment
Explanation:
The diagrams has been made in the attachment section. Please refer.
When an atoms oxidation number decreases in a reaction then it’s being reduced. the answer for that question is B
