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suter [353]
3 years ago
6

HELP PLEASE

Chemistry
2 answers:
ololo11 [35]3 years ago
8 0
Third choice because the others make no sense
erik [133]3 years ago
5 0

Answer:  It is a salt because it is formed by the reaction of an acid and a base.

Explanation:  When an Acid and Base reacts with each other, the product formed is known as Salt. This reaction is a kind of neutralization reaction in which acid is being neutralized by the base.

Thus Sodium Chloride is a salt because it is formed by the neutralization reaction of the strong acid like HCl and strong base like NaOH

                      HCl(aq) + NaOH (s)  →  NaCl(s)

Thus all the other options given are wrong.

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What is the constant Kc for Cd²+(aq)+4Br-(aq) CdBr4²-(aq)​
Tasya [4]

Answer:

im only in 6th grade TwT

Explanation:

LOL

5 0
3 years ago
A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL
snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43        

pH = 14 - pOH = 14 - 4.43 = 9.57

Now, the perchloric acid added will react with ammonia:

n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O    

n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles

Finally, we can calculate the pH of the resulting solution:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98  

pH = 14 - 4.98 = 9.02

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0
3 years ago
On average what is the time between collisions of a xenon atom at 300 K and (a) one torr pressure; (b) one bar pressure.
Amanda [17]

Answer:

(a). 132 × 10^-9 s = 132 nanoseconds.

(b)..176.5 pico-seconds.

Explanation:

(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;

Speed = [ (8 × R × T)/ Mm × π]^1/2.

Where Mm = molar mass, T = temperature and R = gas constant.

Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.

The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;

Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.

Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.

Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.

Degree of collision = 7.55 × 10^6 s^-1.

Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.

(b). At one bar;

1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.

6 0
3 years ago
A proton transfer reaction can occur when a carbonyl compound is placed in an aqueous acidic solution. Water and a charged conju
madam [21]

Answer:

refer attachment

Explanation:

The diagrams has been made in the attachment section. Please refer.

3 0
3 years ago
How do I know which substance is being reduced? ​
Llana [10]
When an atoms oxidation number decreases in a reaction then it’s being reduced. the answer for that question is B
8 0
3 years ago
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