What happens when the density of a medium increases?

Given the three equations below, what is the heat of reaction for the production of glucose, C6H12O6, as described by this equat

UkoKoshka [18]

Answer:

- 1273.02 kJ.

Explanation:

This problem can be solved using Hess's Law.

Hess's Law states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes. This law is a manifestation that enthalpy is a state function.

We should modify the given 3 equations to obtain the proposed reaction:

6C(s) + 6H₂(g) + 3O₂(g) → C₆H₁₂O₆(s),

We should multiply the first equation by (6) and also multiply its ΔH by (6):

6C(s) + 6O₂(g) → 6CO₂(g), ∆H₁ = (6)(–393.51 kJ) = - 2361.06 kJ,

Also, we should multiply the second equation and its ΔH by (6):

6H₂(g) + 3O₂(g) → 6H₂O(l), ∆H₂ = (6)(–285.83 kJ) = - 1714.98 kJ.

Finally, we should reverse the first equation and multiply its ΔH by (- 1):

6CO₂(g) + H₂O(l) → C₆H₁₂O₆(s) + 6O₂(g), ∆H₃ = (-1)(–2803.02 kJ) = 2803.02 kJ.

By summing the three equations, we cam get the proposed reaction:

6C(s) + 6H₂(g) + 3O₂(g) → C₆H₁₂O₆(s),

And to get the heat of reaction for the production of glucose, we can sum the values of the three ∆H:

∆Hrxn = ∆H₁ + ∆H₂ + ∆H₃ = (- 2361.06 kJ) + (- 1714.98 kJ) + (2803.02 kJ) = - 1273.02 kJ.

6 0

2 years ago

Read 2 more answers

What is the number of mole equivalents of H2 produced by the reaction of 1 mole equivalent of Mg (m) with H2SO4 (aq)?

Inga [223]

Answer:

We'll have 1.00 mol H2

Explanation:

Step 1: Data given

Number of moles of Mg = 1.00 moles

Step 2: The balanced equation

Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)

Step 3: Calculate moles of H2

For 1 mol Mg we need 1 mol H2SO4 to produce 1 mol MgSO4 and 1 mol H2

We'll have 1.00 mol H2

8 0

2 years ago

Guess how many water molecules self-ionize in one liter of water! a) 7 moles b) 1 mole c) 10,000,000 moles d) 0.0000001 moles

Rudiy27

Answer:

D)

Explanation:

This seems like a weird question

Water is held together by covalent bonds. The amount of energy required to break these bonds so that water would split into it's respective ions is pretty high. The chances that any one of the molecules floating in 1L of water get enough energy to spontaneously burst into it's ions is slim to none.

So, D) seems like the most likely answer

6 0

2 years ago

You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid

Art [367]

Answer:

$V_1=2.49mL$