Answer:
1. λ = 5.60 m
, 2. T = 5.80 s 3. v = 0.966 m/s 4. A = 0.315 m
Explanation:
1. The definition of wavelength is the distance between two consecutive maximums or minimums, so that the wave is repeated, in this case they give us the distance between two consecutive maximums, therefore
λ = 5.60 m
2. the period is the time it takes for the wave to start repeating itself, going through the same point. They give time to go from the highest point to the lowest point, which is the time for half a wavelength, so the time for a wavelength is
T = 2 t
T = 2 2.90
T = 5.80 s
3. For all waves the speed is the product of the wavelength by the frequency and the frequency is the inverse of the period
v = λ f
f = 1 / T
v = λ / T
v = 5.60 / 5.80
v = 0.966 m / s
4. The amplitude of the wave is the value of the zero displacement point to the maximum displacement point, give the value between the maximum and minimum displacement
A = d / 2
A = 0.63 / 2
A = 0.315 m
Answer:
5Hz
Explanation:
Frequency = No. of waves per second
10 waves are produced in 2 seconds
in one second 10/2 waves are produced
(ie) 5 waves are produced in 1 second
Therefore the frequency of wave is 5 Hz
Answer and Explanation: Kinetic energy is related to movement: it is the energy an object possesses during the movement. it is calculated as:
For the object thrown in the air:
![K=\frac{1}{2}.2.[v(t)]^{2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D.2.%5Bv%28t%29%5D%5E%7B2%7D)
Kinetic energy of the object as a function of time:
Potential energy is the energy an object possesses due to its position in relation to other objects. It is calculated as:
For the object thrown in the air:
Potential energy as function of time:
Total kinetic and potential energy, also known as mechanical energy is
TME = 
+ (
)
TME = 1752
The expression shows that total energy of an object thrown in the air is constant and independent of time.
Answer:
the time it takes for one complete back and forth swing
Explanation:
the Mark's is showing you the time it swings back and forth
Answer:
The maximum safe speed of the car is 30.82 m/s.
Explanation:
It is given that,
The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :
.........(1)
A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet
Put the value of r in equation (1) as :
v = 30.82 m/s
So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.
