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Ahat [919]
3 years ago
8

A series RLC circuit is connected to a 3.80 kHz oscillator with a peak voltage of 3.80 V. It consists of a 3.50 mH inductor, a 2

90. nF capacitor, and a 19.0 ? resistor. If ? = ?0, what is the instantaneous current i?
Physics
1 answer:
olchik [2.2K]2 years ago
3 0

Answer:

instantaneous current will be 59.52 mA

Explanation:

Given data

oscillation F = 3.80 kHz = 3.80 ×10^{3} Hz

voltage V = 3.80 V

inductance L = 3.50 mH  = 3.50 ×10^{-3} H

capacitor C =  290. nF = 290 ×10^{-9} F

resistor R = 19.0 Ω

to find out

the instantaneous current

solution

we know that current I = V / Z

here Z = √(R²+(xl - xc)²)

so first we find xl = 2π×f×L = 2π×3800×3.50 ×10^{-3}

xl = 83.52 ohm

and xc = 1 / 2π×f×C = 1 / 2π×3800× 290 ×10^{-9}

xc = 144.497 ohm

so Z = √(R²+(xl - xc)²)

Z = √(19²+(83.52 - 144.497)²)

Z = 63.84

so that current will be  V / Z

current = 3.80 / 63.84

current = 0.5952 A

so instantaneous current will be 59.52 mA

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2 years ago
Read 2 more answers
Can anyone help me? (physics)
Masja [62]

Answer:

The initial velocity of the golf is 15.7 m/s.

The direction of the golf is 57°.

Explanation:

The following data were obtained from the question:

Time of flight (T) = 2.7 secs

Range (R) = 23 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =.?

Direction (θ) =.?

T = 2U Sine θ /g

2.7 = 2 × U × Sine θ /9.8

Cross multiply

2.7 × 9.8 = 2 × U × Sine θ

26.46 = 2 × U × Sine θ

Divide both side by 2 × Sine θ

U = 26.46 /2 Sine θ

U = 13.23 / Sine θ ... (1)

R = U² Sine 2θ /g

23 = U² Sine 2θ / 9.8

U = 13.23 / Sine θ

23 = (13.23/ Sine θ)² Sine 2θ / 9.8

23 = (175.0329 / Sine² θ) × Sine 2θ / 9.8

23 = 17.8605/Sine² θ × Sine 2θ

Recall:

Sine 2θ = 2SineθCosθ

23 = 17.8605/ Sine² θ × 2SineθCosθ

23 = 17.8605/ Sine θ × 2Cosθ

23 = 35.721 Cos θ /Sine θ

Cross multiply

23 × Sine θ = 35.721 Cos θ

Divide both side by 23

Sine θ = 35.721 Cos θ /23

Sine θ = 1.5531 × Cos θ

Divide both side by Cos θ

Sine θ /Cos θ = 1.5531

Recall:

Sine θ /Cos θ = Tan θ

Sine θ /Cos θ = 1.5531

Tan θ = 1.5531

Take the inverse of Tan

θ = Tan¯¹ (1.5531)

θ = 57°

Therefore, the direction of the golf is 57°

Thus, the initial velocity can be obtained as follow:

U = 13.23 / Sine θ

θ = 57°

U = 13.23 / Sine 57

U = 13.23/0.8387

U = 15.7 m/s

Therefore, the initial velocity of the golf is 15.7 m/s

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Hunter-Best [27]

Answer:

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now we will have

d = \frac{(10 + 0)}{2}\times 1.2

d = 5 \times 1.2

d = 6.0 m

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