Answer:
the answer is the first letter in the alphabet
Answer:
Explanation:
given,
initial velocity of the ball = 20 m/s
angle of ramp = 22°
ball travel at a distance = 5 m
a) for friction less




v = 17.58 m/s
b) considering the friction




v = 17.16 m/s
Sure what do u need help with
At the lowest point on the Ferris wheel, there are two forces acting on the child: their weight of 430 N, and an upward centripetal/normal force with magnitude n; then the net force on the child is
∑ F = ma
n - 430 N = (430 N)/g • a
where m is the child's mass and a is their centripetal acceleration. The child has a linear speed of 3.5 m/s at any point along the path of the wheel whose radius is 17 m, so the centripetal acceleration is
a = (3.5 m/s)² / (17 m) ≈ 0.72 m/s²
and so
n = 430 N + (430 N)/g (0.72 m/s²) ≈ 460 N