Answer:
a

b

c

Explanation:
From the question we are told that
The mass of the bag is 
The normal force experienced is 
The maximum acceleration of the bag is 
Generally this normal force experience by the bag is mathematically represented as

=> 
=> 
=> ![\theta = cos^{-1}[0.9183]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20cos%5E%7B-1%7D%5B0.9183%5D)
=> 
Generally for the bag not to slip , it means that the frictional force is equal to the sliding force

Hence
is mathematically represented as
While
is mathematically represented as

So
=>
=> 
Generally from the workdone equation we have that

Here
is the work done by friction which is mathematically represented as
Here s is the distance covered by the bag
is zero given that velocity at rest is zero
and

so

=> 
substituting 2.55 m/s for v_i and 0.350 for \mu_k we have that

=> 
Answer:
27.8 mph
Explanation:
May I have brainliest please? :)
Answer:
The second law: When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car. This law is expressed by the famous equation F = ma, where F is a force, m is the mass of the car, and a is the acceleration, or change in motion, of the car
Answer:
<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S.I Unit of acceleration is m/s². Acceleration is a vector quantity because it can be represented both in magnitude and in direction.
Acceleration can be represented mathematically as
a = v/t.................................... Equation 1
Where a = acceleration, v = velocity, t= time.
<em>Given: v = 115 m/s, t = 13.0 s</em>
<em>Substituting these values into equation 1</em>
<em>a = 115/13</em>
<em>a = 8.846 m/s² moving east</em>
<em>Thus the planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>