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OverLord2011 [107]
3 years ago
11

A boy runs 400m at an average speed of 4.0m/s he runs the first 200m in 40 s how long does he take to run the second 200m?

Physics
1 answer:
IRISSAK [1]3 years ago
8 0
If he runs at the same speed he will cover next 200m in 40s
that is at the average of 4.0m
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A 25.0 kg bag of peat moss sits in the back of a flatbed truck, driving up a hill. The bag experiences a 225N normal force. The
malfutka [58]

Answer:

a

   \theta  =  23.32^o

b

  \mu_s =  0.27

c

s =  0.948 \  m

Explanation:

From the question we are told that

The mass of the bag is m_b  =  25.0 \  kg

The normal force experienced is F_n  =  225 \ N

The maximum acceleration of the bag is a =  2.40 \  m/s^2

Generally this normal force experience by the bag is mathematically represented as

F_n  =  mg cos \theta

=> 225  =  (25 * 9.8) cos \theta

=> 0.9183  =   cos \theta

=> \theta  = cos^{-1}[0.9183]

=> \theta  =  23.32^o

Generally for the bag not to slip , it means that the frictional force is equal to the sliding force

F_f =  F_s

Hence F_f is mathematically represented as

F_f   =  \mu_s  *  F_n

While F_s is mathematically represented as

F_s   =  m * a

So

\mu_s  *  F_n = m * a

=> \mu_s  *  225 = 25 * 2.40

=> \mu_s =  0.27

Generally from the workdone equation we have that

KE_f - KE_i =  W_f

Here W_f is the work done by friction which is mathematically represented as

W_f  =  m * g * \mu_k * s

Here s is the distance covered by the bag

KE_f is zero given that velocity at rest is zero

and

KE_i = \frac{1}{2}  *  m* v_i^2

so

   \frac{1}{2}  *  m* v_i^2 = m * g * \mu_k * s

=>  \frac{1}{2}  *  v_i^2 =   g * \mu_k * s

substituting  2.55 m/s for v_i and 0.350 for  \mu_k  we have that

     \frac{1}{2}  *  2.55^2 =   9.8 * 0.350 * s

=> s =  0.948 \  m

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3 years ago
How fast can Usain Bolt run if it takes him 9.9 s to run 100m?​
Arte-miy333 [17]

Answer:

27.8 mph

Explanation:

May I have brainliest please? :)

8 0
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Discuss impact of Newton's second law on roads​
ruslelena [56]

Answer:

The second law: When a force is applied to a car, the change in motion is proportional to the force divided by the mass of the car. This law is expressed by the famous equation F = ma, where F is a force, m is the mass of the car, and a is the acceleration, or change in motion, of the car

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A plane lands on a runway with a speed of 115 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m/s2
marin [14]

Answer:

<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

Explanation:

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Acceleration can be represented mathematically as

a = v/t.................................... Equation 1

Where a = acceleration, v = velocity, t= time.

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<em>Substituting these values into equation 1</em>

<em>a = 115/13</em>

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<em>Thus the planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>

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