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strojnjashka [21]
3 years ago
14

If an object has a mass of 50 kg and is accelerating at 2m/s/s, what is the force it will exert?

Physics
1 answer:
Tresset [83]3 years ago
5 0
The formula you're looking for is Force = mass * acceleration. this means the force = 50 * 2, which is 100N
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Which of the following terms describes one’s ability to understand how another person is feeling?
liq [111]

Answer:

Empathy

Explanation:

Empathy: to understand the thoughts, feelings, or emotional state of another person

Appreciation: to show gratitude

Cooperation: is the association for mutual benefit

Commitment: is the agreement to do something.

  • From the definitions above, empathy is the term that describes one’s ability to understand how another person is feeling.
8 0
3 years ago
10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (
MArishka [77]

Answer:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

8 0
2 years ago
What is the path that an electric current follows called
Gwar [14]
I’m sure it’s called a circuit:)
5 0
3 years ago
Read 2 more answers
A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo
Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2

E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

3 0
3 years ago
For a bronze alloy, the stress at which plastic deformation begins is 294 MPa and the modulus of elasticity is 121 GPa. (a) What
FromTheMoon [43]

Answer:

a) load in Newton is 96,138 b) 129.314mm

Explanation:

Stress = force/ area (cross sectional area of the bronze)

Force(load) = 294*10^6*327*10^-6 = 96138N

b) modulus e = stress/ strain

Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3

Strain = change in length/ original length = DL/ 129

Change in length DL = 129 * 2.34*10^ -3 = 0.31347

Maximum length = change in length + original length = 129.314mm

7 0
2 years ago
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