Answer:
the specific heat of the unknown compound is 
Explanation:
Generally the change in temperature of water is evaluated as

Substituting 16.1°C for
and 27.4°C for 


Generally the change in temperature of unknown compound is evaluated as

Substituting 27.4°C for
and 94.3°C for 


Since there is an increase in temperature then heat is gained by water and this can be evaluated as

Substituting 179.1 g for m , 4.18 J/g.C for
(specific heat of water)


Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

By conservation of energy law
Heat lost = Heat gained
Substituting 306.9 g for
, 8459.6J for

Therefore 

The concentration of the reactants and products remain constant. Because the rates of the forward and reverse reaction are equal there is no net change to the amount of reactants or products produced.May 19, 2011
Answer:
In medicine, genetic engineering has been used to mass-produce insulin, human growth hormones, follistim, human albumin, monoclonal antibodies, antihemophilic factors, vaccines, and many other drugs. In research, organisms are genetically engineered to discover the functions of certain genes.
Explanation:
Answer:
the Molar heat of Combustion of diphenylacetylene
= 
Explanation:
Given that:
mass of diphenylacetylene
= 0.5297 g
Molar Mass of diphenylacetylene
= 178.21 g/mol
Then number of moles of diphenylacetylene
= 
= 
= 0.002972 mol
By applying the law of calorimeter;
Heat liberated by 0.002972 mole of diphenylacetylene
= Heat absorbed by
+ Heat absorbed by the calorimeter
Heat liberated by 0.002972 mole of diphenylacetylene
= msΔT + cΔT
= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C
= 17756.48 J + 2842.39 J
= 20598.87 J
Heat liberated by 0.002972 mole of diphenylacetylene
= 20598.87 J
Heat liberated by 1 mole of diphenylacetylene
will be = 
= 6930979.139 J/mol
= 6930.98 kJ/mol
Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene
= 
The atomic number of an atom is determined by the number of protons it has..
It is also the whole number shown on the periodic table