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ss7ja [257]
3 years ago
13

13. You push with 56 N on a 15-kg box, and there is a 23-N force of friction. How fast will the box accelerate?

Physics
1 answer:
Flura [38]3 years ago
4 0

Answer:

The acceleration is 2.2 m/s^2

Explanation:

In the attached image, we can see the free body diagram. And using the second law of Newton it will be possible to find the acceleration of the box.

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How wide is the moon
goldfiish [28.3K]

The moon is very nearly a sphere (ball shape).  We usually talk
about the "diameter" of a sphere, not its width. 

The moon's diameter is about  2,159 miles or 3,475 kilometers. 
That's about  27% (a little over a quarter) of the Earth's diameter.

7 0
3 years ago
Read 2 more answers
Calculate the height of a column of carbon tetrachloride, CCl4(l), with a density of 1.59 g/mL that exerts the same pressure as
julia-pushkina [17]

Answer:

1.30 m

Explanation:

The pressure (P) exerted by a column of a liquid can be calculated with the following expression:

P=\rho \times g \times h

where,

ρ is the density of the liquid

g is the gravity

h is the height of the column

If both liquids exert the same pressure:

PHg = PCCl_{4}\\\rho Hg \times g \times hHg = \rho CCl_{4} \times g \times hCCl_{4}\\\rho Hg \times hHg = \rho CCl_{4} \times hCCl_{4}\\hCCl_{4 = \frac{\rho Hg \times hHg}{\rho CCl_{4}} =\frac{13.6g/mL \times 15.2cm}{1.59g/mL} = 130cm=1.30m

6 0
3 years ago
A planet has two
lozanna [386]
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

<u>Moon #1:</u>  (1.262 days)² / (2.346 x 10^4 km)³

<u>Moon #2:</u>  (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

               =  0.1017 day²

Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
7 0
3 years ago
The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object
VashaNatasha [74]

Answer:

m_B > m_A

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

        F = m a

        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

         \frac{F}{m_A} > \frac{F}{m_B}

         m_B > m_A

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

6 0
3 years ago
1. A 61-kg woman doing pull-ups lifts her body a distance of 0.32 meters in 1.8 seconds. What is the power provided by her bicep
Allushta [10]

Answer:

P = mgh/t = 61(9.8)(0.32)/1.8 = 106.275555... ≈ 110 W

Explanation:

Power is the rate of doing work.

The work changes her potential energy.

4 0
2 years ago
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