Answer:
11.515 Joule
Explanation:
Volume of aluminium = V = 4.89×10⁻³ m³
Coefficient of volume expansion for aluminum = α = 69×10⁻⁶ /°C
Initial temperature = 19.1°C
Final temperature = 357°C
Pressure of air = 1.01×10⁵ Pa
Change in temperature = ΔT= 357-19.1 = 337.9 °C
Change in volume
ΔV = αVΔT
⇒ΔV = 69×10⁻⁶×4.89×10⁻³×337.9
⇒ΔV = 114010.839×10⁻⁹ m³
Work done
W = PΔV
⇒W = 1.01×10⁵×114010.839×10⁻⁹
⇒W = 11.515 J
∴ Work is done by the expanding aluminum is 11.515 Joule
The input voltage is 120 V and the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.
<h3>
Input voltage </h3>
The input voltage of the transformer is the voltage of the primary coil and it is calculated as follows;
Ns/Np = Es/Ep
where;
- Ns is the number of turn in the secondary coil
- Np is the number of turn in the primary coil
- Es is the secondary voltage
- Ep is the primary voltage
2X/X = 240/Ep
2 = 240/Ep
Ep = 240/2
Ep = 120 V
Thus, the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.
Learn more about transformer here: brainly.com/question/25886292
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The Answer Is D 32 % Of The worlds production is In the marine ecosystem
Answer:
5900J
Explanation:
Work=Forse*Distance
work = J, Jewls
100*59=5900
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