13. You push with 56 N on a 15-kg box, and there is a 23-N force of friction. How fast will the box accelerate?
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The force between the molecules involved in the bond is 6. 426 *10^-11 Newton
<h3>How to determine the force</h3>
Using the formula:
F = K[q1 x q2]/D^2
where K is coulombs constant =9 *10 ^9 Nm^2/C^2.
q1 and q2 = charges = 1.60x10 -20C
d = distance between the charges = 2x10 -10 m
Substitute the values into the formula
F =
F =
F =
F = Newton
Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton
Learn more about electrostatic force here:
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