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xenn [34]
3 years ago
6

Correct formula for chromium (III) oxide

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
3 0

Answer: Cr203

Explanation: chromium(|||) oxide Is the compound of the formula Cr203. It's one of the principle oxides of chromium and used as a pigment.

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A metal crystallizes in the face‑centered cubic (FCC) lattice. The density of the metal is 12020 kg/m3, and the length of a unit
Fantom [35]

Answer:

  1.7700×10^-22 g

Explanation:

A face-centered-cubic cell contains 4 atoms, so the volume per atom is ...

  (389.80×10^-12 m)³/(4 atoms) ≈ 1.4725×10^-29 m³

Then the mass of 1 atom is ...

  (12020 kg/m³)(1.4725×10^-29 m³) ≈ 1.76995×10^-25 kg

  ≈ 1.7700×10^-22 g

_____

<em>Additional comment</em>

That is the approximate mass of a Palladium atom.

7 0
3 years ago
Read 2 more answers
What is the molarity of a solution if 0.529 moles of LiCl is dissolved in 687 mL of water?
Dominik [7]

Answer:

Molarity of solution = 0.77 (Approx.)

Explanation:

Given:

Moles of LiCl = 0.529

Volume of water  = 687

Find:

Molarity of solution

Computation:

Molarity of solution = [Moles/Volume]1000

Molarity of solution = [0.529/687]1000

Molarity of solution = 0.77 (Approx.)

5 0
3 years ago
I need help!!! the last two answers choices are
Cloud [144]

Answer:

D.atom 2 is not the same , because the mass number is different from atoms 1 and 2

7 0
3 years ago
Measure and record the masses of all metal strips you set out in front of the test tubes
jeka94

Magnesium ribbon dissolves in zinc nitrate and copper nitrate solutions.

Even though the question is incomplete and refers to your practical work, however, I will try to help you as much as I can.

Metals dissolves in solutions of other metals that are lower than them in the electrochemical series. Hence, copper strip will show no change in magnesium nitrate or zinc nitrate solution. A zinc strip will not show any change in magnesium nitrate or zinc nitrate.

However, a magnesium ribbon will dissolve very quickly in zinc nitrate and copper nitrate solutions.

Learn more: brainly.com/question/14396802

3 0
3 years ago
A student adds 10.00 mL of a 2.0 M nitric acid solution to a 100.00 mL volumetric flask. Next, 50.00 mL of a 0.00500 M solution
qwelly [4]

Answer:

0,20M of nitric acid

0,00250M of KSCN

Explanation:

For nitric acid, the dilution is from 10,00mL to 100,00mL. That is a 1/10 dilution. As the initial concentration of nitric acid is 2,0M, the new concentration is: <em>2,0M× (1/10) = </em><em>0,20M of nitric acid</em>

<em></em>

For KSCN the dilution is from 50,00mL to 100,00mL, that is a dilution 1/2. Thus, the new concentration of KSCN is:

<em>0,00500M × (1/2) = </em><em>0,00250M of KSCN</em>

<em />

I hope it helps!

5 0
3 years ago
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