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olchik [2.2K]
3 years ago
14

Question 1. Considering the reaction of the decomposition of N2O5 to form the products NO2 and O2, calculate the average reactio

n rate if at 0.00s the concentration of N2O5 was 1.00 M and at 4.00s it decreases to 0.987 M?
2 N2O5 4 NO2 + O2
4.97 × 10-1 mol/(L × s)
7.27 × 10-2 mol/(L × s)
6.50 × 10-3 mol/(L × s)
3.25 × 10-3 mol/(L × s)
Question 2. What is the oxidation number of sulfur (S) in sulfuric acid (H2SO4)?
-6
+2
+4
+6
Chemistry
2 answers:
GalinKa [24]3 years ago
7 0
<span>
 </span><span> average reaction rate </span><span>= change in concentration / change in time
by putting values we have

 = (1.00M - 0.987M) / (4.00s - 0.00s)
 = 3.25x10^-3 mol/Lsec
this is our conclusion
hope this helps</span>
zepelin [54]3 years ago
4 0

question 2. answer is +4 i took the test

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Lakesha gave three tenths of her cookies to Bailey and five tenths of her cookies to Helen. What fraction of her cookies did Lak
Mashutka [201]

Answer:

a . eight tenths of her cookies

Explanation:

Let the total number of Lakesha's cookies be represented by x.

So that;

She gave three tenths to Bailey = \frac{3}{10} of x

                                                     = \frac{3x}{10}

She gave five tenths to Helen = \frac{5}{10} of x

                                                  = \frac{5x}{10}

Fraction of Lakesha's cookies given away = \frac{3x}{10} + \frac{5x}{10}

                                                      = \frac{3x+ 5x}{10}

                                                      = \frac{8x}{10}

Thus, the fraction of cookies given away by Lakesha is \frac{8}{10}.

6 0
3 years ago
Predict the products that will be formed by the reaction below. Al(s)+Na2SO4(s)—&gt;
Ostrovityanka [42]

Answer:

Al₂(SO₄)₃ and Na

Explanation:

Al has a charge of +3, Na has a charge of +1 and SO₄ has a charge of -2. Since cations and anions will bond we know that Al will bond with SO₄ leaving Na by itself (since this is a single replacement reaction). When Al bonds with SO₄ it makes aluminum sulfate which is Al₂(SO₄)₃ and Na will be left by itself.

3 0
3 years ago
Using the periodic tables, identify the heaviest member of each of the following groups:
Lady_Fox [76]

Answer:

(a) Alkali metals: Francium (Fr)

(b) Chalcogens: Polonium (Po)

(c) Noble gases: Radon (Rn)

(d) Alkaline earth metals: Radium (Ra)

Explanation:

In the periodic table, the atomic mass increases down the group. Therefore, the last element of a group is the heaviest element of the group.

(a) alkali metals: The chemical elements that are present in group 1 of the periodic table, except hydrogen.

<u>The heaviest member of this group is francium (Fr)</u>

(b) chalcogens: The chemical elements that are present in group 16 of the periodic table

<u>The heaviest member of this group is polonium (Po)</u>

(c) noble gases:  The chemical elements that are present in group 18 of the periodic table

<u>The heaviest member of this group is radon (Rn)</u>

(d) alkaline earth metals: The chemical elements that are present in group 2 of the periodic table.

<u>The heaviest member of this group is radium (Ra)</u>

7 0
3 years ago
Using words, explain all steps of dimensional analysis when converting 6.7 hectometers to meters. You must explain the set up of
sleet_krkn [62]

Answer:

  • See below

Explanation:

In order to convert 6.7 hectometers to meters using dimensional analysis, you must use the ratio of hectometers to meters.

There are 100 meters in one hectometer, then you start setting the equality: 100 m = 1 hm.

Dividing both sides by 1 hm you get the fraction form of the ratio, with meters (m) in the numerator and hectometers (hm) in the denominator.

              1m/100hm

Since hm is in the numerator, when you multiply 6.7 hm by the unit ratio the hm will be canceled and the result will have only m:

            6.7hm\times 1m/100hm=0.067m

6 0
3 years ago
if a volume of air occupying 12.0Lat 20celsius is heated to a new temperature of 100 celsius,what would be the new volume
emmasim [6.3K]

Answer:

V₂ = 15.3

Explanation:

Given data:

Initial volume = 12.0 L

Initial temperature = 20°C

Final temperature =100°C

Final volume = ?

Solution:

First of all we will convert the temperature into kelvin.

20°C + 273 = 293 K

100°C + 273 = 373 K

Formula:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 12.0 L × 373 K / 293 k

V₂ = 4476 L.K /293 k

V₂ = 15.3

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

6 0
3 years ago
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