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4 years ago

When you approach a light source that in turn is moving towards you, your speed relative to the emitted light waves _____.?

2 answers:

7 0

This is a trick question:

The Doppler effect states that as you move closer to the source, the frequency of light(or sound/waves in general) increases, but technically the speed of light is always the same speed, even if you are moving at the speed of light.

Thus, the answer would be something along the lines of <u>don't change</u>.

lutik1710 [3]4 years ago

3 0

Remains constant.....it's not like sound in which there is Doppler effect....so I guess it will be constant...as Albert Einstein said !

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The diagram below shows light striking a pane of glass. some of the light is reflected and some of the lightest transmitted. the

Leto [7]

Hi there!!! I hope i'm not late! i'm not sure but i think it might be letter:

B. F and A

If i'm wrong please correct me and explain so that I and everyone else know in the future...Thank you and sorry if i wasn't much help!!!

Have a Brainly Day!!!

5 0

4 years ago

Read 2 more answers

An object is dropped out of an airplane that is moving horizontally at 350 m/s and is 22,000 m above the ground. Ignoring fricti

lilavasa [31]

Answer:

Vx = 350m/s

Vy = 656.99 m/s

Explanation:

at the time of drop, the horizontal velocity of the object is same as of plane.

Since friction is ignored, horizontal velocity remains unchanged.

Vx = 350m/s

but the Vy increases due to gravitational acceleration

V^2 - U^2 = 2as

V: FINAL VELOCITY

U: INITIAL VELOCITY

U = 0 m/s

$v=\sqrt{2as}= \sqrt{2(9.81)(22000)} = 656.99 m/s$

8 0

3 years ago

2. A student is pulling a 11.0 kg sled along flat ground. The students 30.0 kg sister then sits in the sled. The student then ap

iVinArrow [24]

Answer:

Explanation:

The equation for this is

F - f = ma

The thing that gets strange here is that, because the student is pulling his sister on the sled with the rope at an angle, some of his efforts are being wasted. The sled is only going to move forward (horizontally), so the vertical component of that force is useless. He's not actually pulling horizontally with that much force; we have to figure out how much using the following equation:

$F=430cos35$ to get that

F = 352 N

Everything else falls into place quite easily into the equation now:

352 - 180 = 41a and

172 = 41a so

a = 4.2 m/s/s

7 0

3 years ago

A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from

Damm [24]

Answer:

$1.67\cdot 10^{-5} T$

Explanation:

The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:

$B=\frac{\mu_0 I}{2\pi r}$

where:

$\mu_0=4\pi \cdot 10^{-7} H/m$ is the vaacuum permeability

I is the current in the wire

r is the distance from the wire

The direction of the magnetic field lines is tangential to concentric circles around the wire.

In this problem, we have:

$I=37.9 A$ is the current in the wire

$r=45.5 cm = 0.455 m$ is the distance from the wire

Solving for B, we find the magnitude of the magnetic field:

$B=\frac{\mu_0 I}{2\pi r}=\frac{(4\pi \cdot 10^{-7})(37.9)}{2\pi (0.455)}=1.67\cdot 10^{-5} T$

4 0

3 years ago

How many miles of MgCI2 are there in 339g of compound?

harkovskaia [24]

I'm going to answer this by using rounded numbers for the atomic masses. You need only go back and put the numbers in from your periodic table. My answers will be close, but not what you should get.

Find the Molar Mass of MgCl2

Mg = 24 grams

2Cl = 2 * 35.5 = 71 grams

Total = 95 grams

Find the mols in 339 grams

1 mole = 95 grams

x mol = 339

Solve

339 = 95x Divide by 95

339/95 = x

x = 3.67 mols Answer

4 0

3 years ago