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saw5 [17]
3 years ago
9

2. A student is pulling a 11.0 kg sled along flat ground. The students 30.0 kg sister then sits in the sled. The student then ap

plies a 430 N force at an angle of 35° N of E. If the force of friction is 180 N, what is the acceleration of the sister sitting in the sled. (Ensure you draw a free body diagram.)
​
Physics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

Explanation:

The equation for this is

F - f = ma

The thing that gets strange here is that, because the student is pulling his sister on the sled with the rope at an angle, some of his efforts are being wasted. The sled is only going to move forward (horizontally), so the vertical component of that force is useless. He's not actually pulling horizontally with that much force; we have to figure out how much using the following equation:

F=430cos35 to get that

F = 352 N

Everything else falls into place quite easily into the equation now:

352 - 180 = 41a and

172 = 41a so

a = 4.2 m/s/s

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Nesterboy [21]
B. is not a validated bu experimentation

5 0
3 years ago
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A car slows down at -5.00 m/s^2 until it comes to a stop after travelling 15.0 m. How much time did it take to stop?
Xelga [282]
In physics, there are already derived equation that are based on Newton's Law of Motions. The rectilinear motions at constant acceleration have the following equations:

x = v₁t + 1/2 at²
a = (v₂-v₁)/t

where
x is the distance travelled
v₁ is the initial velocity
v₂ is the final velocity
a is the acceleration
t is the time

Now, we solve first the second equation. Since it mentions that the car comes eventually to a stop, v₂ = 0. Then,

-5 = (0-v₁)/t
-5t = -v₁
v₁ = 5t

We use this new equation to substitute to the first one:
x = v₁t + 1/2 at²
15 = 5t(t) + 1/2(-5)t²
15 = 5t² - 5/2 t²
15 = 5/2 t²
5t² = 30
t² = 30/5 = 6
t = √6 = 2.45

Therefore, the time it took to travel 15 m at a deceleration of -5 m/s² is 2.45 seconds.

5 0
3 years ago
Each milligram of glucose has the same amount of energy available to do work. The series B test tubes produced more bacteria per
yKpoI14uk [10]

Answer:

The series A test tube has some left amount of glucose left in it.

Explanation:

Let's assume that a fixed amount of glucose is synthesized, for the fixed quantity the bacteria produced in A and B be x and y respectively,

Therefore, the condition on x and y is,    y > x  as the no. of bacteria present in B is greater.

As a result B would require a greater amount of energy for its functioning, these energy would be derived from the already fixed amount of glucose present.

A test tube would also require the energy for its x number of bacteria, but it is less than that of B.

Therefore, there would be some unused glucose left in Test Tube Series A which has unused energy.

4 0
3 years ago
Locomotion is the act of staying stationary. <br><br> True <br> False<br><br> 20 POINTS
Fittoniya [83]

Answer:

False

Explanation:

Locomotion is associated with movement.

The word is derieved from two Latin words,

Loco----place

Motio----to move.

8 0
3 years ago
When 180 joules of work is done to push a box horizontally 15.3 meters, how much
AnnZ [28]

Answer:

11.76Newtons

Explanation:

Workdone = Force * distance

Given

Workdone = 180joules

Distance = 15.3 metres

Required

Force

From the formula;

Force - Work/distance

Force = 180/15.3

Force = 11.76Newtons

Hence the required force is 11.76Newtons

5 0
3 years ago
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