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Zolol [24]
3 years ago
15

Who discovered white blood cells

Physics
1 answer:
Grace [21]3 years ago
4 0
Gabriel Andral hope i helped
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A 9 m3 container is filled with 300 kg of r-134a at 10°c. what is the specific enthalpy (kj/kg) of the r-134a in the container?
andreev551 [17]
Given the mass of R-134a m = 300kg; Volume of the container V = 9  cu. meter; Temperature of R-134a T = 10 degrees Celsius; 
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg. 
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.  
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
8 0
3 years ago
A flywheel with a radius of 0.200m starts from rest and accelerates with a constant angular acceleration of 0.900rad/s2.
kobusy [5.1K]

Answer:

The magnitude of the radial acceleration is 0.754 rad/s²

Explanation:

Given;

radius of the flywheel, r = 0.2 m

initial angular velocity of the flywheel, \omega_i = 0

angular acceleration of the flywheel, a = 0.900 rad/s².

angular distance, θ = 120⁰

the angular distance in radian = \frac{120}{180} \pi = \frac{2 \pi}{3}  \ rad

Apply the following kinematic equation to determine the final angular velocity;

\omega _f^2 = \omega _i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 + 2(0.9)(\frac{2\pi}{3} )\\\\\omega _f^2 = 3.7699\\\\\omega _f = \sqrt{ 3.7699} \\\\ \omega _f = 1.942 \ rad/s

The magnitude of the radial acceleration is calculated as;

\alpha _r = \omega ^2r\\\\\alpha _r  = (1.942)^2 (0.2)\\\\\alpha _r  =0.754 \ rad/s^2

Therefore, the magnitude of the radial acceleration is 0.754 rad/s²

4 0
3 years ago
Answer this question ​
mash [69]

Answer:

That's ezy

Explanation:

so you add sponge and Bob so then. you go to earth to get milk because your dad didn't came back you you add Spider-Man so you can get taco bell but that's when you don't find the earth but SpongeBob can drink water

so that how I got 25

7 0
2 years ago
How are distance and time related when describing motion?
Bingel [31]
an object moves along a straight line, the distance travelled can be represented by a distance-time graph. In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving
3 0
3 years ago
A wave has a wavelength of 4. 9 m and a velocity of 9. 8 m/s. The medium through which this wave is traveling is then heated so
tatiyna

The wavelength of a wave is obtained by taking the ratio of wave speed and frequency.

The wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

What is frequency of a wave?

The number of oscillations completed by a wave in one second is known as the frequency of a wave. It is expressed as the ratio of the velocity of the wave to its wavelength.

Given data-

The wavelength of the wave is, \lambda = 4.9 \;\rm m.

The velocity of the wave is, v = 9.8 m/s.

The mathematical expression for the frequency of the wave is,

f = \dfrac{v}{\lambda}

Solving as,

f = \dfrac{9.9}{4.9}\\\\f =2 \;\rm Hz

Now, with constant frequency and the double magnitude of velocity (v' = 2 × 9.8 = 19.6 m/s). The wavelength of the heated wave is calculated as,

f = \dfrac{v'}{\lambda'}

here,

\lambda' is the wavelength of the heated wave.

Solving as,

2 = \dfrac{19.6}{\lambda'}\\\\\lambda' = \dfrac{19.6}{2}\\\\\lambda' = 9.8 \;\rm m

Thus, we can conclude that the wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

Learn more about the frequency of wave here:

brainly.com/question/1324797

3 0
3 years ago
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