Who discovered white blood cells

Scilla [17]

A Cat is a secondary source

5 0

4 years ago

A 250 g toy car is placed on a narrow 60-cm-diameter track with wheel grooves that keep the car going in a circle. The 1.5 kg tr

Lady_Fox [76]

Answer:

$\omega_{t}=-3.9 rpm$

Explanation:

Let's use the conservation of angular momentum here. If there is a conservation the addition of both must be zero.

$L_{c}+L_{t}=0$

The momentum of inertia of both are:

$I_{c}=m_{c}R^{2}$

$I_{t}=m_{t}R^{2}$

The angular momentum is the product between angular velocity and momentum of inertia.

$I_{c}\omega_{c}+I_{t}\omega_{t}=0$

Let's solve it for ω(t).

$\omega_{t}=-\frac{I_{c}\omega_{c}}{I_{t}}$

$\omega_{t}=-\frac{m_{c}R^{2}\omega_{c}}{m_{t}R^{2}}$

But $\omega=V/R$

R is the radius R=D/2 = 30 cm = 0.3 m
V is the steady speed V = 0.74 m/s

$\omega_{t}=-\frac{m_{c}R^{2}*V/R}{m_{t}R^{2}}$

$\omega_{t}=-\frac{m_{c}V}{m_{t}R}$

$\omega_{t}=-\frac{0.25*0.74}{1.5*0.3}$

$\omega_{t}=-0.41 rad/s$

Knowing that 2π rad is a rev. We have.

$\omega_{t}=-3.9 rpm$

The minus sign means the track is moving opposite of the car.

I hope it helps you!

4 0

4 years ago

Read 2 more answers

two 0.5 kg carts, one red and one green, sit about half a meter apart on a low friction track, you push on the red one with the

pshichka [43]

Answer:

The work done by you on the two cart system is 2 N-m

Explanation:

Work done is the product of force and displacement.

W = F * D

Substituting the given values we get -

W =

$4 * (0.17+0.33)\\= 2$

The work done by you on the two cart system is 2 N-m

6 0

4 years ago

Assume that Young’s modulus for a new material is known to be 2.25 × 1011 /2

Lady bird [3.3K]

Answer:

Maximum force, $F_{max} = 42 kN$

Explanation:

Maximum Stress, $\sigma_{max} = 2.1 * 10^{7} N/m^{2}$

The diameter of the material, d = 50.5 mm = 0.0505 m

The area of the material, $A = (\pi d^{2} )/4$

$A = \frac{\pi * 0.0505^{2} }{4} \\A = 0.002 m^{2}$

The formula for the maximum stress that the material can take is given by:

$\sigma_{max} = \frac{F_{max} }{A} \\2.1 * 10^7 = \frac{F_{max} }{0.002}\\F_{max} = 2.1 * 10^7 * 0.002\\F_{max} = 4.2 * 10^4 N\\F_{max} = 42 kN$

4 0

3 years ago

Manita carries a box of mass 40kg. What is the wieght of the box?

laila [671]

Answer:

40kg

Explanation:

that the answer

7 0

3 years ago