Is there multiple choice answers?
Answer:
12000j
mass=1500kg
velocity=4m/s
Kinetic Energy (K E) = 1/2 mv^2
=1/2*1500(4^2)
=1*750*16
=12000j
<span>3 AgNO3 + FeCl3 = Fe(NO3)3 + 3 AgCl
moles AgNO3 = 18.0 g/ 169.87 g/mol=0.106
moles FeCl3 required = 0.106/3=0.0353
mass FeCl3 = 162.206 g/mol x 0.353 mol=5.73 g
mass FeCl3 in excess = 32.4 - 5.73 =26.7 g.
26.7 gram of excess reactant remain after the reaction is over</span>
Answer:
Barium carbonate powder is stirred add pulp in the entry, the vitriol that the adds solubility then reaction that makes the transition is filtered and is obtained the barium sulfate filter cake and liquid after the transition.
Answer is 355 grams.
Explanation:
Given the molecular weights:
M
r
N
a
O
H
=
40
g
m
o
l
M
r
N
a
2
S
O
4
=
142
g
m
o
l
The analogy of the moles will be held constant:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
1
n
N
a
O
H
n
N
a
2
S
O
4
=
2
For each one, substitute:
n
=
m
M
r
Therefore:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
2
S
O
4
=
2
200
40
x
142
=
2
200
⋅
142
40
x
=
2
200
⋅
142
=
2
⋅
40
x
x
=
200
⋅
142
2
⋅
40
=
100
⋅
142
40
=
10
⋅
142
4
=
1420
4
=
=
710
2
=
355
g
r
a
m
s
(or just use a calculator)