A mixture of punch contains 1 quart of lemonade, 2 cups of grape juice, 4 tablespoons of honey, and gallon of sparkling water. F

Question

3 years ago

6

A mixture of punch contains 1 quart of lemonade, 2 cups of grape juice, 4 tablespoons of honey, and gallon of sparkling water. F

ind the percentage of the punch mixture that comes from each ingredient. Round your answers to the nearest tenth of a percent.

Mathematics

1 answer:

Veseljchak [2.6K] · Answer 1 · 2022-04-11T10:24:06+03:00

<h2>Answer:</h2><h2>(i) Percentage of lemonade = $\frac{64}{356} (100)$ = 17.98 %</h2><h2>(ii) Percentage of grape juice = $\frac{32}{356} (100)$ = 8.99 %</h2><h2>(iii) Percentage of honey = $\frac{4}{356} (100)$ = 1.12 %</h2><h2>(iv) Percentage of sparkling water = $\frac{256}{356} (100)$ = 71.91%</h2>

Step-by-step explanation:

By unit conversion,

1 cup = 16 table spoons

1 quart = 64 table spoons

1 gallon = 256 table spoons

1 quart of lemonade = 64 table spoons

2 cups of grape juice = 16 * 2 = 32 table spoons

4 tablespoons of honey = 4 table spoons

1 gallon of sparkling water = 256 table spoons.

Total quantity in table spoons = 64 + 32 + 4 + 256 = 356 table spoons

(i) Percentage of lemonade = $\frac{64}{356} (100)$ = 17.98 %

(ii) Percentage of grape juice = $\frac{32}{356} (100)$ = 8.99 %

(iii) Percentage of honey = $\frac{4}{356} (100)$ = 1.12 %

(iv) Percentage of sparkling water = $\frac{256}{356} (100)$ = 71.91%