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AURORKA [14]
3 years ago
15

Ravi and Tina were working on a project based on ‘Changes around us’, for which they were observing different changes occurring

in their daily life. They went to kitchen where they saw their mother was cooking food on LPG stove. Ravi said that burning of LPG in LPG stove involves chemical change. But Tina argued that both physical and chemical changes are involved in this process. According to you who is correct and why?
Note: will mark Brainliest but Please do not copy answers from the internet!
Chemistry
2 answers:
kupik [55]3 years ago
5 0

Answer: It includes both a physical and chemical change

Explanation: Because the gas is turning into fire which is physical and the gas is giving out heat which is chemical

Savatey [412]3 years ago
3 0

Answer:

There is both physical and chemical change happening.

Physical change is a reversible change but chemical change is irreversible.

When the LPG burns, there is both physical and chemical change happening,

  • When LPG comes out of the cylinder, it is converted from liquid to gaseous state - <u>physical change</u>
  • When the gas burns in air - <u>chemical change</u>

Therefore Tina is correct in the argument.

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Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




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3 years ago
I need help with this question
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When testing for hydrogen gas in the laboratory a glowing splint is inserted into the gas which results in a pop sound. What is
Advocard [28]
C. Exothermic reaction I guess
5 0
3 years ago
Question
andreev551 [17]

Answer:

Sln

n=m/mr

n=25/100

n=0.25mole of Caco3

Malality =number of moles/volume (divided by number of moles both sides)

volume =Malality /number of moles

v=0.125/0.25

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I hope this help

5 0
3 years ago
Hot water enters a double-pipe counter-flow water-to-oil heat exchanger at 220°7 and leaves a 100°F. Oil enters at 70°F and leav
il63 [147K]

Answer:

Oil has the smaller heat capacity. The effectiveness of the heat exchanger is 0.80.

Explanation:

Part 1:

In order to know which fluid has the smaller heat capacity we need to consider the heat equation below:

Q = CΔT, where Q is the heat exchanged, C is the heat capacity and ΔT is the variation in temperature.

As the heat exchange is the same for both fluids, the smaller the temperature variation, the smaller the heat capacity.

Water: ΔT = 120 °F  

Oil: ΔT = 80 °F  

Therefore, oil is the fluid with the smallest heat capacity.

Part 2:

The effectiveness of a counter-flow heat exchanger is given by the equation bellow:

E = \frac{Th1 - Th2}{Th1 - Tc1} \\

Th1: initial temperature of the hot fluid

Th2: final temperature of the hot

Tc1: initial temperature of the cold fluid

E = \frac{220 - 100}{220 - 70} \\E = 0.8

7 0
3 years ago
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