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nlexa [21]
3 years ago
14

What is the surface area of a cylinder with base radius 2 and height 9

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

The surface area of a cylinder with a base radius and a height of 9 is 138.23

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Both the ranges and the interquartile ranges for the data sets are the same.
aleksley [76]

Answer:

to find range of interquartile sets of data

you see 5 vertical lines 1 is start point 2 is start of 2nd quartile 3 is start of 3rd quartile and also represents the median.  the 4th start of 4th quartile and 5th is very end point.

Therefore the interquartile is from start line 2 to start line 4

apply to each by if it says 10 and 34 then we show workjings 34-10 = 24 and that is the range once we deduct data from each other.

Therefore full range is start line 1 to end line 5

if this says 2 to 45 then full range is 45-2 = 43 and apply to each boxplot.

Step-by-step explanation:

6 0
2 years ago
Factor the expression using the GCF.<br><br> 18h+30k<br><br> The factored form is <br> .
Murljashka [212]

Answer:

6(3h+5k)

Step-by-step explanation:

18h+30k

Factors of 18:

1, 2, 3, 6, 9, 18

Factors of 30:

1, 2, 3, 5, 6, 10, 15, 30

GCF of 18 and 30: 6

18h+30k = 6(3h+5k)

Check your answer:

6(3h+5k)

6(3h) + 6(5k)

18h + 30k

Hope this helps!

7 0
2 years ago
I believe the answer is C. however, I'm not 100% sure.
Brut [27]

The answer would be C. You’re correct! Because there are 3 blue marbles @ $1 each that amounts to a possible $3 gain for Mark. Evan has the chance to get $4. Cayla also can make $3 like Mark.

7 0
2 years ago
How do you rationalise this surd?
Ksivusya [100]

\frac{1 +  \sqrt{3} }{ \sqrt{2} }   \times  \frac{ \sqrt{2} }{ \sqrt{2} } =  \frac{ \sqrt{2}  +  \sqrt{6}  }{2}
here you go
5 0
2 years ago
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Which rigid transformation would map ΔAQR to ΔAKP?
Virty [35]
Rotation around point a

8 0
3 years ago
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