(03.02 LC)

Sample of 76 G of NaCl is dissolved to make 1 L of a solution what is the molarity of the solution

natima [27]

Molarity = Moles/Liter

Use the molecular atomic mass of NaCl to convert from grams to moles.
Molecular mass of NaCl is the sum of its atomic masses. Look at the periodic table to find these. Na is 23 g/mol and Cl is 35.5 g/mol ,
so NaCl = 23 + 35.5 = 58.5 g/mol

multiply to cancel out grams
76 g NaCl * (1mol / 58.5 g NaCl) = 1.3 mol NaCl

over 1 Liter is just 1.3 M NaCl

6 0

3 years ago

Read 2 more answers

The mass of each WtWt isotope is measured relative to C−12C−12 and tabulated below. Use the mass of C−12C−12 to convert each of

Nadya [2.5K]

The question is incomplete , the complete question is;

The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.

Wt-296 = 24.6622

Answer:

The atomic mass of Wt-296 is 195.9464 amu.

Explanation:

1 amu is defined as 1 by twelfth of the carbon-12 mass.

Mass of an isotope Wt-296 = 24.6622

Mass of an isotope Wt-296 in amu = M

$M\times \frac{1}{12 amu}=24.6622$

$M=24.6622\times 12 amu=295.9464 amu$

The atomic mass of Wt-296 is 195.9464 amu.

8 0

3 years ago

Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong ac

Leona [35]

<span>From left to right:

1) starts at high pH, no buffer zone - strong base being titrated with strong acid
2) starts at low pH, no buffer zone - strong acid being titrated with strong base
3) starts at low pH, shows a buffer zone - weak acid titrated with strong base
4) starts at high pH, shows a buffer zone - weak base titrated with strong acid
5) polyprotic due to two equivalence points
</span>

4 0

3 years ago

Read 2 more answers

Each of the chemically active Period 2 elements forms stable compounds in which it has bonds to fluorine.(a) What are the names

Softa [21]

The names of the compound are lithium fluoride ( LiF) , beryllium difluoride (BeF2) , Boron trifluoride (BF3) , carbon tetrafluoride (CF4) , nitrogen trifluoride (NF3) , oxygen difluoride (OF2) .

Lithium is the first element of period 2 which reacts with fluorine to form LiF ( lithium fluoride ) . it is an inorganic compound . it is also a colorless solid . it is less soluble in water . it is chemically stable because of its comparable molecular mass .

Beryllium is the second element of period 2 which reacts with fluorine to give beryllium difluoride (BeF2) . it is inorganic compound . it is highly soluble in water. it is also a stable compound . it have low melting point .

Boron is the third element of period 2 which reacts with fluorine to form

BF3 (Boron trifluoride ) . it is a inorganic compound . it is colorless and toxic gas forms . it is stable in dry atmosphere but its octet is not satisfied .

Carbon is the 4th element of the period 2 which reacts with fluorine to form carbon tetrafluoride (CF4) . it is not soluble in water . it is a greenhouse gas . it dissolves in oil. it is very stable compound .it forms covalent bond .

Nitrogen is the 5th element of period 2 which reacts with fluorine to form nitrogen trifluoride (NF3) . it is also a inorganic compound . it is colorless and non-flammable . it is a stable gas at room temperature .

Oxygen is the 6th element of period 2 which reacts with fluorine to form oxygen difluoride (OF2) . it is colorless poisonous gas . it is partially stable or relatively stable .

Neon is a noble gas and also a stable element . it is odorless and colorless . so it is nonreactive . so it doesn't form bond with fluorine .

<h3>Learn more about Fluorine here :</h3>

brainly.com/question/3494441

#SPJ4

8 0

2 years ago

Beryllium oxide, Beo, is an electrical insulator. How

egoroff_w [7]

Answer:

There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

Explanation:

We can calculate the number of moles (η) of BeO as follows:

$\eta = \frac{m}{M}$

Where:

m: is the mass = 250 g

M: is the molar mass = 25.0116 g/mol

Hence, the number of moles is:

$\eta = \frac{250 g}{25.0116 g/mol} = 10.0 moles$

Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

I hope it helps you!

3 0

3 years ago