Answer:
0.0400 g for the example given below.
Explanation:
pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.
- By definition, .
- NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: .
- From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: .
- Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: .
- We also know that . Take the antilog of both sides: .
- Solve for the mass of NaOH: .
Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:
The melting points of sugar and salt are above 20°C.
<h3>What is melting point?</h3>
The melting points of substances refer to the temperature at which solid substances gain enough energy to become liquids.
The room temperature is approximately 20°C. At this temperature, sugar and salt are solids. This means that the melting temperature of both substances is above 20°C.
More specifically, sugar will melt around 180 °C while salt will melt at a temperature slightly above 800 °C.
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The concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M. Details about concentration can be found below.
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.
no of moles of NH42CO3 = 192g ÷ 96g/mol = 2 mol
Concentration of solution = 2 moles ÷ 2.15L
Concentration of solution = 0.93M
Therefore, the concentration of a solution of 192 grams dissolved to make 2150 mL of solution is 0.93M.
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Answer:
D. As one variable increases, the other variable also increases
Answer:
The answer is option D, that is, carbon and carbon monoxide