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boyakko [2]
3 years ago
15

The statements that are most characteristic of league

Chemistry
1 answer:
Usimov [2.4K]3 years ago
7 0

formed by citys?

Idk message me when if im wrong

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HELP ASAP! GIVING BRAINLIEST!! 15 POINTS
Rufina [12.5K]

I think Kinetic energy forms <em>Motion energy </em>and Potential energy forms <em>Gravitational Potential energy.</em>

5 0
3 years ago
Write and balance the half-reaction for the oxidation of white phosphorous P4 to the phosphate ion PO3^−4 in a basic solution.
aalyn [17]

Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.

P₄ +16H₂O + 32OH⁻ ⟶ 4PO₃⁻⁴ + 32H⁺ +32OH⁻

Final reaction :

P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻

A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

The concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half-reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction.

For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH- ions to balance the H+ ions in the half reactions (which would give H2O).

Learn more about Half reactions here : brainly.com/question/2491738

#SPJ4

3 0
2 years ago
A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl
Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

  • Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
  • Mass of solution = 392 g
8 0
3 years ago
Which metal is most likely to form more than one kind of positively charged ion?
nataly862011 [7]
C. Nickel, hope this helps!
4 0
3 years ago
B) A company president would like to offer a 4.00 L cylinder containing 500 g of chlorine in the new catalog. The cylinders you
Yuri [45]

Answer:

43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.

Explanation:

Ideal gas law is:

PV = nRT

<em>Where P is pressure in atm</em>

<em>V is volume = 4.00L</em>

<em>n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):</em>

<em>500g * (1mol / 70.90g) = 7.052 moles</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 25°C + 273 = 298K</em>

To solve the pressure, P:

P = nRT/V

P = 7.052mol*0.082atmL/molK*298K / 4.00L

P = 43.1atm is the pressure using gas law.

Van der Waals equation is:

P + a(\frac{n}{V})^2 * (V-nb) = nRT

<em>Where a is 6.58L²atm*mol⁻²</em>

<em>b = 0.056Lmol⁻²</em>

Solving for pressure:

P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}

P  = \frac{nRT}{(V-nb)}-a(\frac{n}{V})^2

P  = \frac{7.052mol*0.082atmL/molK*298K}{(4.00L-7.052mol*0.056L*mol)}-6.58L^2mol^{-2}(\frac{7.052mol}{4.00L})^2

P = 172.323 / 3.6051 - 20.4866

P = 27.2atm using Van der Waals Law

8 0
2 years ago
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