Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
You do cross multiplication so multiply 29 by 38 and then divide it by 78 which gives you answer of 14.128 cm
Answer:
I think it's not my level ques. !!
sowy >.<
Answer:
Beth is incorrect.
It is a translate to the right 5 units and up 1 unit.
When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.
When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.
Step-by-step explanation:
So
is actually a translated 5 units and up 1 unit. Why?
Let's take there point (0,0) and figure out what the new point is on the translated graph.
We need to figure out when the inside of our square root for g is 0. This is where the graph of g will start at and continue on.
x-5=0 when x=5 ( I added 5 on both sides).
So let's plug in 5 to see what the new point is.




So the new graph, g, starts at the point (5,1).
Answer:
<em>y = 13</em>
Step-by-step explanation:
y = 13