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3 years ago

Increasing the temperature increases the rate of a many reactions by:

1 answer:

3 0

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

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Need help with balancing equations

solniwko [45]

The balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

<h3>What are balanced chemical equations?</h3>

Balanced chemical equations are equations in wgich the moles of each species on both sides of the reaction are equal.

To balance chemical equations, numerical coefficients are placed in front of the species in the reaction.

The balanced equations of the reaction are as follows:

$3Pd + 4H_3PO_4 \rightarrow Pd_3(PO_4)_4 + 6H_2 \\$

$C_{11}H_{24} + 17O_2 \rightarrow 11CO_2 + 12H_2O \\$

$2Al(HCO_3)_3 + 3H_2SO_4\rightarrow Al_2(SO_4)_3 +6CO_2 +6H_2O \\$

Therefore, the balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

Learn more about balancing equations at: brainly.com/question/11904811

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7 0

3 years ago

Quiz the solubility constant of your compound depends on the amount of hydrogen bonds formed between the compound molecules and

FromTheMoon [43]

Whats the question? I need to know to help....

5 0

3 years ago

In an extraction experiment similar to your expt. 4, you attempt to separate 2-naphthol from cyclohexane, both of which are diss

Viktor [21]

Answer:

[a]. 108 mL.

[b].

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

Explanation:

The chemical equation for the reaction between 2-naphthol and Sodium hydroxide is given below as:

C₁₀H₈O + NaOH --------------------------------------------------> C10H7O⁻ Na⁺ + H₂O.

The C10H7O⁻ Na⁺ is the aqueous phase.

The molarity of Sodium Hydroxide is = [ (mass of sodium hydroxide ) ÷ molar mass sodium hydroxide × volume] × 1000.

The molarity of sodium hydroxide = [ (5/40) × 100] × 1000 = 1.25 M.

The number of moles of 2-naphthol = mass / molar mass = 20 / 144.17 = 0.138 moles.

Recall that, the formula for the number of moles = concentration × volume. Therefore, the volume of sodium hydroxide is given below as:

Volume of sodium hydroxide = the number of moles of sodium hydroxide ÷ concentration of sodium hydroxide = 0.138 ÷ 1.25 = 0.108L = 108 mL.

In order to efficiently isolate relatively pure cyclohexane from the ether layer, the following process must be followed:

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

7 0

4 years ago

The substances sodium (Na), oxygen (O2), and sodium oxide (Na2O) participate in this chemical reaction: 4Na + O2 ? 2Na2O. Which

nordsb [41]

Here we have to choose the best statement, among the given, in the chemical reaction between the substance sodium (Na) and oxygen (O₂) to form Na₂O.

The suitable statement is sodium oxide is created by the B. chemical reaction.

The reaction between Na and O₂ is 4Na + O₂ = 2Na₂O.

The compound Na₂O is entirely is a new compound and not generated by the rearrangement of the reactant. Here the sodium and oxygen is destroyed and forms Na₂O.

There is no separate atoms in Na₂O it is a compound made by the two atoms Na and O₂.

In a mixture of the three substances sodium oxide can be separated from Na and O₂ but it depends upon the physical property of the reactant and product. If the reactant and product both are in gaseous state they cannot be separated by any physical methods.

5 0

4 years ago

State whether the following statements are true or false. If false, explain why. (a) A reaction stops when equilibrium is reache

Elden [556K]

Answer:

(a) False;

(b) False;

(c) False;

(d) True.

Explanation:

(a) When equilibrium is reached, the forward reaction rate becomes equal to the reverse reaction rate, that's why the molarity of each species remains constant, but reactions don't stop.

(b) According to the principle of Le Chatelier, an increase in molarity of either reactants or products would lead to a disturbance of equilibrium. This disturbance would lead to the shift of equilibrium towards the side which would minimize such a disturbance.

(c) Equilibrium constant is only temperature-dependent, it's independent of molarity, pressure, volume etc. of any species present in the reaction.

(d) The greater the initial molarity of reactants, the more products can be formed, e. g., since the ratio of products to reactants should be kept constant, the larger the amount of reactants, the greater the amount of products formed to keep a constant ratio.

7 0

3 years ago