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vesna_86 [32]
3 years ago
12

Write the formula to iron (III) oxide and iron (III) carbonate

Chemistry
1 answer:
NemiM [27]3 years ago
4 0

Answer:

iron (III) oxide =Fe2O3

iron(III) carbonate =Fe2(CO3)3

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Write the simple equation that describes the action of the enzyme catalase.
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Here we have to write a simple equation which describes the action of the enzyme catalase.

The equation is: The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }

Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P

Where E, S, ES and P are enzyme, substrate, complex and product respectively.

The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }, where K_{m} is the Michaelis constant.

[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.    

5 0
3 years ago
Manganese forms several oxides when combined with oxygen. One of the oxides (Oxide 1) contains 63.2% of Mn and another oxide (Ox
Nina [5.8K]

Explanation:

Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

A. One of the oxides (Oxide 1) contains 63.2% of Mn.

Mass of the oxide = 100g

Mass of Mn = 63.2 g

Mass of O = 100 - 63.2

= 36.8 g

Ratio of Mn to O = 63.2/36.8

= 1.72

Another oxide (Oxide 2) contains 77.5% Mn.

Mass of oxide = 100 g

Mass of Mn = 77.5 g

Mass of O = 100 - 77.5

= 22.5 g

Ratio of Mn to O = 77.5/22.5

= 3.44

Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.

B.

Oxide 1

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

Oxide 2

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

3 0
3 years ago
Which two formulas represent compounds
SVEN [57.7K]

CO2 ; H20- They are the only ones that, on both sides, combined with another element and bonding of atoms

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3 years ago
Number of SO2 molecules in 1.28 mol of SO2
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Answer:

7.7056 x 10^23

6 0
3 years ago
For the reaction between aqueous solutions of acetic acid (CH3COOH) and barium hydroxide, Ba(OH)2, 1. Write the balanced molecul
Crazy boy [7]

Answer:

2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)

Explanation:

When acetic acid solution and barium hydroxide solution react together to give an aqueous solution of barium acetate and water

The balanced chemical reaction will be given by

2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)

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