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Answer:
B. 333 in.2
Step-by-step explanation:
The area of the base is 81^2
lateral is 45 x 4 = 180^2 (9x5x4)
180^2 add the 72 pyramid = 252^2 + base of 81^2 = 333^2
Composite figueres i do like this as shown to you a few seconds ago.
The triangle shows us just the height
4 inches
We can see that height is smaller central isosceles height across the center base point.
We also can remember to use the length 9inches but divide by 2 and get each triangle area this way.
4 x 1/2 base = 4x 1/2 4.5 = 4 x 2.25 = 9^2 each right side triangle
9 x 8 = 72^2
we add the areas 72+ 81+lateral 180 = 333 inches^2
Asa has 15 dimes and 32 quarters.
Step-by-step explanation:
Given,
Total coins = 47
Worth of coins = $9.50 = 9.50*100 = 950 cents
1 dime = 10 cents
1 quarter = 25 cents
Let,
Number of dimes = x
Number of quarters = y
According to given statement;
x+y=47 Eqn 1
10x+25y=950 Eqn 2
Multiplying Eqn 1 by 10
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 15
Putting y=32 in Eqn 1
Asa has 15 dimes and 32 quarters.
Keywords: linear equation, elimination method
Learn more about elimination method at:
#LearnwithBrainly
First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
be the number of pets and 
is the probability of owning the number of pets
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let