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Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Opposite sides ofa parallelogram are equal.

Therefore, AB= CD and AD= BC.

Diagonals of a parallelogram bisect each other.

Measure of opposite angles of a parallelgram also equal.

So, <ADC= <ABC and <BAD=<BDC

Since diagonal of a parallelogram bisect each other so AC and BD are intersecting at the point E.

Hence, AE= CE and BE= DE.

Hence, the correct choice is 4)AE=CE.

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Which is the equation of the parabola?

mestny [16]

Answer:

y = -1/20(x + 3)²

Step-by-step explanation:

<u>Consider the parent function:</u>

y = x²

The graph of the function open up and the vertex is at the origin, the point (0, 0)

Now, if it opens down, it means it is a reflection of the parent function over x axis, hence it has a negative coefficient, the function becomes:

y = -x²

The vertex is shifted to the point (-3, 0). It means the function also translated left by 3 units, the function becomes:

y = -(x + 3)²

<u>Since all the options have 1/20 as a coefficient, our function is:</u>

y = -1/20(x + 3)²

This is option B

6 0

2 years ago

Calculate the highest common factor (HCF) for 64

lord [1]

Answer:

1 2 4 8 16 32 64

Step-by-step explanation:

prime factors of 64 is 2 so

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6 0

2 years ago

Read 2 more answers

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$