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3 years ago

PICTURES INCLUDED HELP NEEDED

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Opposite sides ofa parallelogram are equal.

Therefore, AB= CD and AD= BC.

Diagonals of a parallelogram bisect each other.

Measure of opposite angles of a parallelgram also equal.

So, <ADC= <ABC and <BAD=<BDC

Since diagonal of a parallelogram bisect each other so AC and BD are intersecting at the point E.

Hence, AE= CE and BE= DE.

Hence, the correct choice is 4)AE=CE.

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For ΔABC, which two relationships are true?

Phoenix [80]

The two correct relationships are:

$cos(\theta)=\frac{AB}{AC} = sin(90-\theta)\\\\sin(\theta)=\frac{BC}{AC} = cos(90-\theta)$

<h3>What is a right-angled triangle?</h3>

The triangle shown is a right-angled triangle

Considering < $(90-\theta)^o$

$cos(90-\theta)=\frac{BC}{AC} \\\\sin(90-\theta)=\frac{AB}{AC}\\\\tan(90-\theta)=\frac{AB}{BC}$

Considering < $\theta$

$cos(\theta)=\frac{AB}{AC} \\\\sin\theta)=\frac{BC}{AC}\\\\tan(\theta)=\frac{BC}{AB}$

Comparing < $\theta$ and < $(90-\theta)^o$ , the true statements are:

$cos(\theta)=\frac{AB}{AC} = sin(90-\theta)\\\\sin(\theta)=\frac{BC}{AC} = cos(90-\theta)$

Learn more on trigonometry here: brainly.com/question/20519838

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2 years ago

Find the size of angle a

ozzi

Answer:

36 degrees

Step-by-step explanation:

4a+3a+2a+a=360

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A=36

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3 years ago

Examine the diagram. It is not drawn to scale.

Readme [11.4K]

119 as c=62 A=61 so

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2 years ago

ADDING FRACTIONS:

bazaltina [42]

Here is your answer:

$\frac{4}{11} + \frac{3}{8}$

$\frac{4}{11}\times 8 = \frac{32}{88}+\frac{3}{8} \times 11 =\frac{33}{88}$
$32 + 33 = 65 =\frac{65}{88}$

$= \frac{65}{88}$

Therefore the answer is "65/88."

Hope this helps!

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