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3 years ago

Total number of electrons present in 1.8 grams of water is

Chemistry

1 answer:

Liono4ka [1.6K]3 years ago

5 0

1 mole of water = 18 grams (you can find this by finding mass of two hydrogen and one oxygen which is (1*2) + 16 = 18)

1.8 grams = 0.1 moles

1 H2O molecule has 10 electrons so 0.1 moles can be computed as:

(6.023*10^23)*(0.1)*10 = 6.023*10^23 electrons

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1. Addition of which of the following will increase the solubility of CaCO3 in water? Consider the equilibrium process:

kolbaska11 [484]

Answer: HCl

Explanation:

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CaCO 3 (s) + 2HCl(aq) → CaCl 2 (aq) + H 2CO 3(aq)

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3 years ago

Determine whether each molecule given below is polar or nonpolar. of2

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Answer : The molecule $OF_2$ is a polar molecule.

Explanation :

Polar molecule : When the arrangement of the molecule is asymmetrical then the molecule is polar.

Non-polar molecule : When the arrangement of the molecule is symmetrical then the molecule is non-polar.

The given molecule is, $OF_2$

The electronegativities of oxygen and fluorine are different. The molecular geometry of $OF_2$ is bent. As, Fluorine is more elctronegative than the oxygen. So, the arrows putting towards the more electronegative element i.e, fluorine. These arrows do not balance each other. Due to this, the asymmetrical arrangement of these bonds makes the molecule polar.

Hence, the given molecule $OF_2$ is polar.

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3 years ago

400. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution

ch4aika [34]

<u>Answer:</u> The molecular weight of protein is $1.14\times 10^2g/mol$

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

or,

$\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT$

where,

$\pi$ = Osmotic pressure of the solution = 0.0861 atm

i = Van't hoff factor = 1 (for non-electrolytes)

$m_{solute}$ = mass of protein = 400 mg = 0.4 g (Conversion factor: 1 g = 1000 mg)

$M_{solute}$ = molar mass of protein = ?

$V_{solution}$ = Volume of solution = 5.00 mL

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$0.0861atm=1\times \frac{0.4g\times 1000}{M\times 100}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\M=1136.62g/mol=1.14\times 10^2g/mol$

Hence, the molecular weight of protein is $1.14\times 10^2g/mol$

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Softa [21]

A heterogeneous mixture is a mixture that it's components can be easily seen and separated.

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