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lozanna [386]
3 years ago
11

Total number of electrons present in 1.8 grams of water is

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
5 0

1 mole of water = 18 grams (you can find this by finding mass of two hydrogen and one oxygen which is (1*2) + 16 = 18)

1.8 grams = 0.1 moles

1 H2O molecule has 10 electrons so  0.1 moles can be computed as:

(6.023*10^23)*(0.1)*10 = 6.023*10^23 electrons

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The play will be more  appealing to a younger audience.

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A younger audience will more likely appreciate current pop hits rather than classical score.

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What is the molar mass of HCl??
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Why can a liquid change to take the shape of its container but NOT expand to fill the container itself?
tiny-mole [99]

Answer: Option (C) is the correct answer.

Explanation:

Molecules in a liquid have less force of attraction as compared to solids. But liquid molecules have more force of attraction as compared to gases.

Since molecules of a gas are held together by weak Vander waal forces, therefore, they expand to fill the container whereas molecules in a liquid are not expanded in a container like gases because of more force of attraction within molecules of liquids as compared to gases.

Hence, a liquid can take the shape of container in which it is kept.

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What does a positive H look like on a potential energy diagram?
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A sample of methane gas, CH4, occupies 3.25 L at temperature of 19.0 o C. If the pressure is held constant, what will be the tem
Artemon [7]

Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V₁) = 3.25 L

Initial temperature (T₁) = 292 K

Final volume (V₂) = 10 L

Final temperature (T₂) =?

V₁/T₁ = V₂/T₂

3.25 / 292 = 10 / T₂

Cross multiply

3.25 × T₂ = 292 × 10

3.25 × T₂ = 2920

Divide both side by 3.25

T₂ = 2920 / 3.25

T₂ = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

Therefore the final temperature of the gas is 625.46 °C

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