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aleksandrvk [35]
3 years ago
11

Arrange the elements in order of increasing electronegativity. Use the periodic table to help you arrange the elements.

Chemistry
2 answers:
spayn [35]3 years ago
8 0
Silicon, chlorine , sulfur , phosphorus
JulsSmile [24]3 years ago
8 0

The question is incomplete, the elements to be arranged as required are shown in the image attached to this answer.

Answer:

K<Mg<P<O

Explanation:

Electronegativity is the ability of an atom of an element in a compound to attract the shared electrons of a bond towards itself. Atoms of highly electronegative elements tend to polarize a covalent bond leading to polar covalent bonds and dipole moments. Electronegativity increases across the period but decreases down the group hence the arrangement of elements in the answer provided above.

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I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity o
likoan [24]
We know that molarity = mol/L, so:

1.5 M = x mol/0.345 L

1.5 M * 0.345 L = x mol => 0.5175 mol

0.5175 mol/0.250 L = 2.07 M

Your new molarity of the solution will be 2.07 M.
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3 years ago
Use the image to answer the question.
Lena [83]

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1. the process of plants taking in sunlight and creating oxygen

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What is the importance of a special habitat?
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They meet all the environmental conditions an organism needs to survive
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2 years ago
In IR spectroscopy, we normally talk about "frequencies" when in reality we are referring to wavenumbers. What is the mathematic
Svetach [21]

Answer:

Here's what I get.

Explanation:

(b) Wavenumber and wavelength

The wavenumber is the distance over which a cycle repeats, that is, it is the number of waves in a unit distance.

\bar \nu = \dfrac{1}{\lambda}

Thus, if λ = 3 µm,

\bar \nu = \dfrac{1}{3 \times 10^{-6} \text{ m}}= 3.3 \times 10^{5}\text{ m}^{-1} = \textbf{3300 cm}^{-1}

(a) Wavenumber and frequency

Since

λ = c/f and 1/λ = f/c

the relation between wavenumber and frequency is

\bar \nu = \mathbf{\dfrac{f}{c}}

Thus, if f = 90 THz

\bar \nu = \dfrac{90 \times 10^{12} \text{ s}^{-1}}{3 \times 10^{8} \text{ m$\cdot$ s}^{-1}}= 3 \times 10^{5} \text{ m}^{-1} = \textbf{3000 cm}^{-1}

(c) Units

(i) Frequency

The units are s⁻¹ or Hz.

(ii) Wavelength

The SI base unit is metres, but infrared wavelengths are usually measured in micrometres (roughly 2.5 µm to 20 µm).

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The SI base unit is m⁻¹, but infrared wavenumbers are usually measured in cm⁻¹ (roughly 4000 cm⁻¹ to 500 cm⁻¹).

8 0
3 years ago
) In another experiment, the student titrated 50.0mL of 0.100MHC2H3O2 with 0.100MNaOH(aq) . Calculate the pH of the solution at
andrew11 [14]

Answer:

Explanation:

moles of acetic acid = 500 x 10⁻³ x .1 M

= 5 X 10⁻³ M

.005 M

Moles of NaOH = .1 M

Moles of sodium acetate formed = .005 M

Moles of NaOH left = .095 M

pOH = 4.8 + log .005 / .095

= 4.8 -1.27875

= 3.52125

pH = 14 - 3.52125

= 10.48

6 0
3 years ago
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