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bezimeni [28]
3 years ago
9

A doctor orders 2.0 mg of morphine. The vial of morphine on hand is 40. mg per 4.0 mL. How many milliliters of morphine should y

ou administer to the patient.
Chemistry
1 answer:
Dmitry [639]3 years ago
6 0
The correct answer would be 2.0 ml
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Lab: Limiting Reactant and Percent Yield
creativ13 [48]

Answer : If a substance is the limiting reactant, then it limits the formation of products because in the reaction it is present in limited amount.

Explanation :

While observing a chemical reaction, we can tell about whether a reactant is limiting or excess.

Step 1 : first write the chemical reaction and then balanced the chemical equation.

C_2H_4+H_2\rightarrow C_2H_6

Step 2 : convert the given masses into the moles if mass of C_2H_4 is 10.5 g and molar mass of C_2H_4 is 28 g/mole and the mass of hydrogen is 0.40 g and molar mass of hydrogen is 2 g/mole.

\text{moles of }C_{2}H_{4}=\frac{10.5g}{28g/mole}=0.375moles

\text{moles of }H_{2}=\frac{0.40g}{2g/mole}=0.20moles

Step 3 : Now we have to determine the limiting reagent and excess reagent.

\text{ moles of }C_{2}H_{4}\text{ in excess}=0.375-0.20=0.175\text{moles}

Now we conclude that C_{2}H_{4} is the limiting reagent and hydrogen is an excess reagent.

Hypothesis :

Limiting reagent : It is the reagent in the chemical reaction that is totally consumed when the chemical reaction is complete.  Limiting reagent limits the formation of products.

7 0
2 years ago
Read 2 more answers
How many grams of glucose are in 11.5 moles?
qaws [65]

There are 2071.4662 grams of glucose in 11.5 moles.

Per 1 mole there are 180.15588 grams of glucose. 180.5588 x 11.5 =2076.4262

5 0
3 years ago
in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
kolezko [41]

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5

mol of element G :

\tt mol=\dfrac{4}{16}=0.25

mol ratio A : G = 0.5 : 0.25 = 2 : 1

4 0
2 years ago
Imagine a 15kg block moving with a speed of 20m/s. Calculate the kinetic energy of this block.
SSSSS [86.1K]

The kinetic energy formula is;

  • KE=\frac{m.v^2}{2}

The variable m represents the mass. Its unit is kilogram. We are informed that the mass of the object is 15kg. The variable v represents the linear velocity. Its unit is meter per second. We are informed that the linear velocity of the object is 20m/s. Let's find the kinetic energy of the object by substituting these values in the formula.

  • KE=\frac{15kg.(20m/s)^2}{2}
  • 2.KE=15kg.400m^2/s^2
  • 2.KE=(6000)kgm^2/s^2
  • KE=(3000)kgm^2/s^2=3000J
5 0
1 year ago
A water molecule consists of an oxygen atom and two hydrogen atoms covalently bonded in a bent shape. Oxygen however, attracts t
77julia77 [94]

Answer:

D.

Explanation:

Water is polar, for one thing. Polar mixes with polar, nonpolar mixes wih nonpolar. This leaves D.

6 0
3 years ago
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