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Phantasy [73]
3 years ago
14

How many moles is 1.25 x 1024 atoms of bromine?

Chemistry
1 answer:
Irina-Kira [14]3 years ago
8 0

Answer:

2.08 moles (3 s.f.)

Explanation:

number of moles

= number of atoms ÷ Avogadro's constant

Avogadro's constant= 6.022 ×10²³

Thus, number of moles

= 1.25×10²⁴ ÷ (6.022 ×10²³)

= 2.08 moles (3 s.f.)

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Hardness in groundwater is due to the presence of metal ions, primarily Mg2 and Ca2 . Hardness is generally reported as ppm CaCO
Maslowich

Answer:

  • 0.0144 M
  • 1440 ppm

Explanation:

Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In

We use the volume of EDTA consumed in the titration to <u>calculate the moles of Ca⁺² ions</u>:

  • 0.012 L * 0.0600 M * \frac{1molCa^{+2}}{1molEDTA} = 7.20x10⁻⁴ mol Ca⁺²

Now we <u>calculate the molarity</u>:

  • 7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M

To calculate in ppm, we <u>use the moles of Ca⁺² and convert to mg of CaCO₃:</u>

  • 7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃
  • 7.20x10⁻⁴ mol CaCO₃ * 100g/mol * \frac{1000mg}{1g} = 72 mg CaCO₃

Finally, <u>the concentration in ppm</u> is:

  • 72 mg CaCO₃ / 0.050L = 1440 ppm
5 0
3 years ago
Picture a neutral S atom. This neutral atom will have
ser-zykov [4K]

Answer:

it will have 6 valence electrons

it will gain electrons

charge will be 2-

4 0
3 years ago
If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
3 years ago
Identify whether longhand notation or noble-gas notation was used in each case below.
n200080 [17]

Answer:

The given electronic configuration is long hand notation.

Explanation:

Long-hand notation of representing electronic configuration is defined as the arrangement of total number of electrons that are present in an element.

Noble-gas notation of representing electronic configuration is defined as the arrangement of valence electrons in the element. The core electrons are represented as the previous noble gas of the element that is considered.

The given electronic configuration of potassium (K):  

The above configuration has all the electrons that are contained in the nucleus of an element. Thus, this configuration is a long-hand notation.

6 0
3 years ago
What is the hydrogen ion concentrate of orange juice that has a ph of 1
enot [183]

ITS HYDROGEN IONS CONCERNTATION IS MORE BECAUSE ON THE LEFT SIDE OF PH SCALE THERE IS INCREASING OF H+ IONS AND PH IS LESS THAN 7 IS MORE ACIDIC IN NATURE

6 0
3 years ago
Read 2 more answers
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