First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
Explanation:
Relation between length of a curve and angle is as follows.
l = 
where, R = radius of curve
= angle in radians
Also, l = 
.......... (1)
If curve has a degree of curvature 
for standard length s, then
R = 
........... (2)
Now, substitute the value of R from equation (2) into equation (1) as follows.
l = 
If s = 30 m, then calculate the value of l as follows.
l =
= 
= 452 m
thus, we can conclude that the length of the curve is 452 m.
Hi there,
NH3 has the weight of 17.03 grams, and SF6 has the weight of 146.06 grams
so in total, there is 163.09 grams
Hope this helps :P
Answer:
D
Explanation:
D. V1P1 / T1=V2P2 / T2 is correct
Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.
10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F
The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).
Where H = Heat, s =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.
On plugging the values we get:
H = 135.0 g × 4.184 J/g.⁰C×(29.444 - 10.222) ⁰C
Or, H = 10857.354 J or 10.857 kJ.
Thus 10857.354 J or 10.857 kJ heat will be needed to raise the temperature.
