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ki77a [65]
2 years ago
6

Binigyan ang isang liham ng pasasalamat at gagawin ko rin siya ng kabutihan sa ibang pagkakataon​

Chemistry
1 answer:
anzhelika [568]2 years ago
8 0

Answer:

what language do you speak?

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A 1-cubic-centimeter cube of sodium reacts more rapidly in water at 25°C than does a 1-cubic-centimeter cube of calcium at 25°C.
ki77a [65]
B) nature of the metals
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3 years ago
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Definition: This is the energy that comes to Earth from the Sun.
laiz [17]

Answer:

well to me it is called natural energy

7 0
2 years ago
What is the volume in L of a 0.825 mole sample of Ar at 600 mm Hg and 300 K?
Natali5045456 [20]

Answer:

V = 25.7 L

Explanation:

To find the volume of Argon (Ar), you need to use the Ideal Gas Law equation. This looks like:

PV = nRT

In this formula,

        > P = pressure (atm)

        > V = volume (L)

        > n = number of moles

        > R = constant (0.0821 L*atm/K*mol)

        > T = temperature (K)

While there is a different constant that can be used if you want to keep the pressure in mmHg, there is a more common constant used when the pressure is in atm. So, to find the volume, you need to (1) convert mmHg to atm (by dividing by 760) and then (2) calculate the volume (using Ideal Gas Law).

<u>(Step 1)</u>

600 mm Hg              1 atm
-------------------  x  ---------------------  =  0.789 atm
                              760 mm Hg

<u>(Step 2)</u>

PV = nRT

(0.789 atm) x V = (0.825 mole)(0.0821 L*atm/K*mol)(300 K)

(0.789 atm) x V = 20.32

V = 25.7 L

5 0
2 years ago
The magnesium atom in chlorophyll A. is used to pass excited electrons on to pheophytin B. is coupled to the production of ATP C
goblinko [34]

Answer:

B. is coupled to the production of ATP

Explanation:

The magnesium in chlorophyll acts as an activator of enzymes associated with energy metabolism, especially respiratory enzymes and others that act on phosphorylated substrates such as ATP.

7 0
3 years ago
- How many grams of NaCl are in 0.7L of a 3M solution?
muminat

Answer:

In 0.7 liters (700 ml) there are 122, 85 grams of NaCl

Explanation:

We calculate the weight of 1 mol of NaCl:

Weight 1 mol NaCl= Weight Na + Weight Cl= 23+35,5 g= 58,5g/mol

1 mol NaCl-------58,5 g

3mol NaCl -------x= (3mol NaClx58,5 g)/1 mol= 175, 5 g

3M (175,5 g in this case)---> 3 moles in 1 L of solution

1 L-----175,5 g NaCl

0,7L--x= (0,7Lx175,5 g NaCl)/1L =122,85 g NaCl

5 0
3 years ago
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