Answer:
A) Radium
i don't think that group 2 has period 7, it has only up to period 6 so it's probably Radium :))
Answer:
We have:
M
g
(
s
)
+
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
(
g
)
LHS
Mg= 1
H= 1
Cl= 1
RHS
Mg= 1
Cl=2
H=2
To make Cl and H have 2 on both sides, we place a 2 in front of the HCl
M
g
(
s
)
+
2
H
C
l
(
a
q
)
→
M
g
C
l
2
(
a
q
)
+
H
2
(
g
)
LHS
Mg=1, H=2, Cl=2
RHS
Mg=1, H=1, Cl=2
Thus the equation is balanced and the coefficient of Mg is 1, which is understood so it is not written in the final equation.
Explanation:
Answer:
1. A photon is emitted by the atom.
2. More energy is emitted or absorbed for case 2
Explanation:
The Bohr's model of the atom was based on quantum mechanics idea. He suggested that electrons move in specific spherical orbits round the nucleus.
The claims of his model emphasized on the premise that electrons only move in permissible orbits or energy levels round the nucleus.
The ground state is the lowest energy state available where n= 1.
The excited state is energy levels of n = 2,3,4 .....
Problem 1
For an electron to return to the ground state from a higher energy level, i.e from 5 to 2 in case 1, energy is emitted in form of photons.
Problem 2
More energy is emitted or absorbed when an electron moves from a higher energy level to a more lower one or jumps from a lower energy level to a more higher one.
Answer is: <span> mole ratio of heptane vapor to octane vapor is </span>2,8 : 1.
p(C₇H₁₆) = 31 torr.
p(C₈H₁₈) = 11 torr.
x(C₇H₁₆) = 0,5.
x(C₈H₁₈) = 0,5.
p total = (x(C₇H₁₆) · p(C₇H₁₆)) + (x(C₈H₁₈) · p(C₈H₁₈)) = 0,5· 31 torr + 0,5·11 torr = 21 torr.
The mole fraction of heptane in the vapor is:
p(C₇H₁₆) ÷ p total) = 15,5 torr ÷<span> 21 torr = 0,74. </span>
<span>The mole fraction of octane in the vapor is:
</span>p(C₈H₁₈) ÷ p total = 5.5 torr ÷ 21 torr = 0,26.
Mole ratio heptane vapor ÷ octane vapor:
0,74 ÷ 0,26 = 2,8.
Answer:
sure me no have friends either
mega nut
