Answer:
Explanation:
The main thing for this equation is to follow the amount on each side. Count each element on each side. Then by looking at the numbers figure out what numerical digit would make them equal.
For example:
On the left we have
Cu=1 and Cl=2.
But on the right we have
Cu=1 and Cl=3.
In order for them to be the same, we must add a coefficient of 3 to CuCl2 (aq0 on the left and a coefficient of 3 to Cu(s) on the right.
<h3>
Answer:</h3>
1000 g CCl₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.93 × 10²⁴ molecules CCl₄
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1003.77 g CCl₄ ≈ 1000 g CCl₄
Answer:
Atoms are neither created, nor distroyed, during any chemical reaction ... Chemical reactions are represented on paper by chemical equations. For example, hydrogen gas (H2) can react (burn) with oxygen gas (O2) to form water (H20). ... Write 'balanced' equation by determining coefficients that provide equal numbers of ...
Explanation:
Answer:
P2O3
Explanation:
Firstly, we know that the phosphorus would absorb oxygen from air to form its oxide. We already know the mass of the phosphorus, we can get the mass of the oxygen by subtracting the mass of the phosphorus from the mass of the oxide.
The mass of the oxygen is 2.57 - 1.45 = 1.12g
From here, we covert these masses to moles by dividing by the atomic masses of phosphorus and oxygen respectively.
The atomic mass of phosphorus is 31 while that of oxygen is 16.
P = 1.45/31 = 0.046774193548
O = 1.12/16 = 0.07
We now divide by the smallest which is that of phosphorus.
P = 0.046774193548/ 0.046774193548= 1
O = 0.07/ 0.046774193548 = 1.5
We then multiply the answers by 2 for conversion to whole numbers. Making P = 2 and O = 3
The empirical formula is thus P2O3
* Mole ratio:
C2H4 + 3 O2= 2 CO2 + 2 H2O
1 mole C2H4 --------------- 2 moles H2O
8.00 moles C2H4 ---------- ?
8.00 x 2 / 1 => 16 moles of H2O
Therefore:
1 mole --------- 22.4 L at ( STP)
16 moles ------- ?
16 x 22.4 / 1 => 358.4 L
hope this helps!
