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2 years ago

8

When 1.0 g of solid NaOH (Triangle Hsoln = –445.1 kJ/mol) dissolves in 10 L of water, how much heat is released?

2 answers:

victus00 [196]2 years ago

8 0

Answer:

11.1 kJ

Explanation:

oee [108]2 years ago

4 0

The heat being released is calculated by multiplying the amount of NaOH used for making the solution. We are given a delta H that is equal to -445.1 kJ / mol. This value is per mole NaOH. Calculation is as follows:

-445.1 kJ / mol NaOH (1.0 g NaOH ) ( 1 mol NaOH / 40 g NaOH ) = -11.1 kJ

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Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

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Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol$

Now, molarity of ethanol solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M$

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol$

Now, molarity of sucrose solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L} (1 mL = 0.001 L)\\= 0.94 M$

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol$

Now, molarity of sodium chloride solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M$

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

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