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trasher [3.6K]
3 years ago
8

When 1.0 g of solid NaOH (Triangle Hsoln = –445.1 kJ/mol) dissolves in 10 L of water, how much heat is released?

Chemistry
2 answers:
victus00 [196]3 years ago
8 0

Answer:

11.1 kJ

Explanation:

oee [108]3 years ago
4 0
The heat being released is calculated by multiplying the amount of NaOH used for making the solution. We are given a delta H that is equal to -445.1 kJ / mol. This value is per mole NaOH. Calculation is as follows:

-445.1 kJ / mol NaOH (1.0 g NaOH ) ( 1 mol NaOH / 40 g NaOH ) = -11.1 kJ
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Amiraneli [1.4K]

Answer:

3.35*10^{23}\ SrCrO_4\ molecules

Explanation:

We\ are\ given\ that,\\No.\ of\ moles\ of\ SrCrO_4=0.556\\Hence,\\As\ we\ know\ that,\\No.\ of\ particles=Avagadro's\ Constant*No.\ of\ moles\\We\ already\ know\ that\ Avagadro's\ Constant=6.022*10^{23}\\Here,\\No.\ of\ SrCrO_4\  molecules= 6.022*10^{23}*0.556\\Hence,\\No.\ of\ SrCrO_4\  molecules=3.348*10^{23} molecules\ \approx 3.35*10^{23}\ SrCrO_4\ molecules

7 0
3 years ago
Calculate the amount of heat required to melt 2108 g of water. The enthalpy of fusion of water is ΔHfus=6.010 kJ/mol.
vesna_86 [32]

since the unit for the heat of fusion is kJ/mol, you're going to have to convert the grams into moles in order to cancel out the unit. After that, you can solve like normal.

6 0
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How many moles are in 25.2g of KMnO4?
Zolol [24]
When finding the moles in a compound you have to know the grams. In this case, 25.2 grams are given for KMnO4. To find the moles you would divide the amount of grams by the molar mass of KMnO4. The molar mass of KmnO4 is 158.034. You you would now divide 25.2 by 158.034 which is 0.15946 moles. Depending on how many decimal places the questions asks for is dependent on you. I just went with 5 significant figures. 
4 0
3 years ago
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What phase change occurs during evaporation?
vlabodo [156]
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3 years ago
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What is the molecular formula of the following compound: NH_CI, molar mass = 51.5 g/mol?
Helen [10]

Answer:

Explanation:

Explanation:

As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.

In your case, you know that the empirical formula is

NH Cl

    2

, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be

1:2:1.

What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.

Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.

molar mass empirical formula×n=molar mass compound

To get the molar mass of the empirical formula, use the molar masses of its constituent atoms

14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈

51.5 g/mol

This means that you have

51.5g/mol×n=51.5g/mol

As you can see, you have

n=1.

This means that the empirical formula and the molecular formula are equivalent,

NH Cl.

    2

6 0
3 years ago
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